使用 PHP 将 URL 中的空格替换为 %20

Using PHP Replace SPACES in URLS with %20

提问by David

I'm looking to replace all instances of spaces in urls with %20. How would I do that with regex?

我希望用 %20 替换 url 中的所有空格实例。我将如何用正则表达式做到这一点？

Thank you!

谢谢！

回答by Pascal MARTIN

No need for a regex here, if you just want to replace a piece of string by another: using str_replace()should be more than enough :

这里不需要正则表达式，如果您只想用另一个字符串替换一段字符串：使用str_replace()应该绰绰有余：

$new = str_replace(' ', '%20', $your_string);

But, if you want a bit more than that, and you probably do, if you are working with URLs, you should take a look at the urlencode()function.

但是，如果您想要更多，并且您可能会这样做，如果您正在使用 URL，则应该查看该urlencode()函数。

回答by Madara's Ghost

Use urlencode()rather than trying to implement your own. Be lazy.

使用urlencode()而不是尝试实现自己的。偷懒。

回答by drosanda

I think you must use rawurlencode() instead urlencode() for your purpose.

我认为您必须使用 rawurlencode() 而不是 urlencode() 来达到您的目的。

sample

样本

$image = 'some images.jpg';
$url   = 'http://example.com/'

With urlencode($str) will result

使用 urlencode($str) 将导致

echo $url.urlencode($image); //http://example.com/some+images.jpg

its not change to %20 at all

它根本没有更改为 %20

but with rawurlencode($image) will produce

但是使用 rawurlencode($image) 会产生

echo $url.rawurlencode(basename($image)); //http://example.com/some%20images.jpg

回答by Vyktor

You've got several options how to do this, either:

您有多种选择来执行此操作，或者：

• urlencode()or rawurlencode()- functions designed to encode URLs for http protocol
• str_replace()- "heavy machinery" string replace
• strtr()- would have better performance than str_replace()when replacing multiple characters
• preg_replace()use regular expressions (perl compatible)

• urlencode()或rawurlencode()- 旨在为 http 协议编码 URL 的函数
• str_replace()- “重型机械”字符串替换
• strtr()- 会比str_replace()替换多个字符时有更好的性能
• preg_replace()使用正则表达式（perl 兼容）

strtr()

strtr()

Assuming that you want to replace "\t"and " "with "%20":

假设你要替换"\t"，并" "用"%20"：

$replace_pairs = array(
  "\t" => '%20',
  " " => '%20',
);
return strtr( $text, $replace_pairs)

preg_replace()

preg_replace()

You've got few options here, either replacing just space ~ ~, again replacing space and tab ~[ \t]~or all kinds of spaces~\s~:

你在这里几乎没有选择，要么只替换 space ~ ~，再次替换 space 和 tab~[ \t]~或所有类型的空格~\s~：

return preg_replace( '~\s~', '%20', $text);

Or when you need to replace string like this "\t \t \t \t"with just one %20:

或者当你需要"\t \t \t \t"用一个替换这样的字符串时%20：

return preg_replace( '~\s+~', '%20', $text);

_{I assumed that you really want to use manual string replacement and handle more types of whitespaces such as non breakable space ( )}

_{我假设您真的想使用手动字符串替换并处理更多类型的空格，例如不可破坏的空格 (  )}

回答by alex347

$result = preg_replace('/ /', '%20', 'your string here');

you may also consider using

你也可以考虑使用

$result = urlencode($yourstring)

to escape other special characters as well

也可以转义其他特殊字符

回答by Jonatas Walker

    public static function normalizeUrl(string $url) {
        $parts = parse_url($url);
        return $parts['scheme'] .
            '://' .
            $parts['host'] .
            implode('/', array_map('rawurlencode', explode('/', $parts['path'])));

    }