C# 无法在 WCF REST 服务中反序列化 XML
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Can't deserialize XML in WCF REST service
提问by Joel.Cogley
I've just started playing with the REST starter kit, and I've hit a road block trying to build my own service. I'm trying to create a service for account management, and I can't get the service to serialize my objects, throwing the following error:
我刚刚开始使用 REST 入门套件，但在尝试构建自己的服务时遇到了障碍。我正在尝试为帐户管理创建服务，但无法让该服务序列化我的对象，从而引发以下错误：
Unable to deserialize XML body with root name 'CreateAccount' and root namespace '' (for operation 'CreateAccount' and contract ('Service', 'http://tempuri.org/')) using DataContractSerializer. Ensure that the type corresponding to the XML is added to the known types collection of the service.
无法使用 DataContractSerializer反序列化具有根名称“CreateAccount”和根命名空间“”（用于操作“CreateAccount”和合同（“Service”，“ http://tempuri.org/”））的XML 正文。确保将 XML 对应的类型添加到服务的已知类型集合中。
Here's the actual code for the service (based off of the 'DoWork' method that came with the project):
这是该服务的实际代码（基于项目附带的“DoWork”方法）：
[WebHelp(Comment = "Creates a Membership account")]
[WebInvoke(UriTemplate = "CreateAccount", RequestFormat = WebMessageFormat.Xml)]
[OperationContract]
public ServiceResponse CreateAccount(CreateAccount request)
{
try
{
// do stuff
return new ServiceResponse()
{
Status = "SUCCESS",
ErrorMessage = ""
};
}
catch (Exception ex)
{
return new ServiceResponse()
{
Status = "ERROR",
ErrorMessage = ex.Message + "\n\n" + ex.StackTrace
};
}
}
And last, but not least, here's the object that's causing all the trouble:
最后但并非最不重要的是，这是造成所有麻烦的对象：
public class CreateAccount
{
public string FirstName { get; set; }
public string LastName { get; set; }
public string Email { get; set; }
public bool SignUpForNewsletter { get; set; }
public string Password { get; set; }
}
Am I missing anything stupid?
我错过了什么愚蠢的东西吗？
Thanks in advance!
提前致谢！
采纳答案by Doanair
It appears the problem is a namespace clash between your method name "CreateAccount" and your input type "CreateAccount".
问题似乎是您的方法名称“CreateAccount”和您的输入类型“CreateAccount”之间的命名空间冲突。
Also, you have to mark your CreateAccount type as a DataContract like so:
此外，您必须将您的 CreateAccount 类型标记为 DataContract，如下所示：
[DataContract]
public CreateAccount
{
[DataMember]
public string LastName { get; set; }
...
}
If you want to keep the same name, you can specify a namespace for the CreateAccount class.
如果要保持相同的名称，可以为 CreateAccount 类指定命名空间。
I noticed you have a return type as well. Ensure the return type is marked with the DataContract attribute as well. Also, specify the return format like so:
我注意到你也有一个返回类型。确保返回类型也用 DataContract 属性标记。另外，像这样指定返回格式：
ResponseFormat = WebMessageFormat.Xml
回答by PaulWarren
If you don't have it already, I think a [DataContract] attribute above your CreatAccount class.
如果您还没有它，我认为您的 CreatAccount 类上方有一个 [DataContract] 属性。
回答by Joel.Cogley
It turns out I was missing an extra value in the [DataContract]attribute on the business object.
结果我[DataContract]在业务对象的属性中遗漏了一个额外的值。
Should be [DataContract(Namespace = "")]
应该 [DataContract(Namespace = "")]
回答by Anthony K
I had a similar problem, but I did have the DataContract attribute. What I was missing though was the xmlns="http://uri.org" attribute from the root element when trying to read the xml back into the object.
e.g.
我有一个类似的问题，但我确实有 DataContract 属性。但是，当尝试将 xml 读回对象时，我缺少的是根元素中的 xmlns="http://uri.org" 属性。
例如
<Root_Element xmlns="http://uri.org"><Child_Element/>...</Root_Element>
