Linux find 中的 -prune 选项有什么作用？
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What does -prune option in find do?
提问by kingsmasher1
I can see the -prune of findnot working correctly. I guess -name "efence*" -pruneoption should select (or find) all files except the one with name efence*right?
我可以看到 -prunefind无法正常工作。我猜-name "efence*" -prune选项应该选择（或查找）除名称以外的所有文件，efence*对吗？
Or am i wrong in my understanding?
还是我的理解有误？
The command i executed:
find * -maxdepth 0 -name "efence*" -prune
我执行的命令：
find * -maxdepth 0 -name "efence*" -prune
Expectation: Select all files at current directory (maxdepth 0) except one with name *efence.
期望：选择当前目录 ( maxdepth 0) 中的所有文件，但名为 *efence 的文件除外。
Please help me to understand -prune
请帮我理解 -prune
采纳答案by OpenSauce
Try
尝试
find * -maxdepth 0 -name "efence*" -prune -o -print
The pruneoption doesprint matching files, if no other options are specified (it still prevents findfrom recursing into matching directories, however).
如果没有指定其他选项，该prune选项会打印匹配的文件（但是，它仍然可以防止find递归到匹配的目录中）。
Edited to add explanation:
编辑添加解释：
findexpressions distinguish between testsand actions. From man find:
find表达式区分tests和actions。来自man find：
The expression is made up of options (which affect overall operation rather than the processing of a specific file, and always return true), tests (which return a true or false value), and actions (which have side effects and return a true or false value), all separated by operators.
-andis assumed where the operator is omitted.If the expression contains no actions other than
-prune,
表达式由选项（影响整体操作而不是特定文件的处理，并始终返回 true）、测试（返回 true 或 false 值）和操作（具有副作用并返回 true 或false 值），全部由运算符分隔。
-and假定省略了运算符。如果表达式不包含除 之外的任何操作
-prune，
So -pruneis an action which has the side effect that findwill not recurse into subdirectories which match the preceding test (in your case, -maxdepth 0 -name "efence*"). But in terms of the truth-value of the expression, it's equivalent to just having
-prune具有副作用的操作也是如此，该操作find不会递归到与前面的测试匹配的子目录中（在您的情况下为-maxdepth 0 -name "efence*"）。但就表达式的真值而言，它等价于
find * -maxdepth 0 -name "efence*" -true
and since you didn't specify any other action, -printis assumed (this assumption is always present as it allows you to type e.g. find . -name "*.java"instead of find . -name "*.java" -print).
并且由于您没有指定任何其他操作，-print因此假设为（此假设始终存在，因为它允许您键入 egfind . -name "*.java"而不是find . -name "*.java" -print）。
Hope that makes sense. The accepted answer at the other threadtalks about the same thing.
希望这是有道理的。另一个线程中接受的答案谈论了同样的事情。
