如何使用 PHP 流式传输媒体文件？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/3785188/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to stream a media file using PHP?
提问by Chetan Sharma
I am trying to build an application in which i have to stream the media files (audio and video) to the browser. I am reading the file through php and send the data to browser. I am using the following code.
我正在尝试构建一个应用程序，我必须在其中将媒体文件（音频和视频）流式传输到浏览器。我正在通过 php 读取文件并将数据发送到浏览器。我正在使用以下代码。
header("Cache-Control: no-cache, must-revalidate"); // HTTP/1.1
header("Expires: Sat, 26 Jul 1997 05:00:00 GMT"); // Date in the past
header("Content-Type: {$file->getMimetype()}");
header("Content-Disposition: inline; filename=".$filename.";");
header("Content-Length: ".strlen($file_content));
echo $file_content;
Every thing is working fine, except when i try to forward the video or audio, (I mean suppose current play location is 0:15 and it directly go to 1:25), media stops and when i press the play button again, it starts from the beginning.
一切正常，除了当我尝试转发视频或音频时（我的意思是假设当前播放位置是 0:15，它直接转到 1:25），媒体停止，当我再次按下播放按钮时，它从头开始。
I think the problem is with the buffering, but can't figure it out. Am i doing something wrong in header or something else is required.
我认为问题在于缓冲，但无法弄清楚。我在标题中做错了什么还是需要其他东西。
Thanks.
谢谢。
采纳答案by Sjoerd
I think you need to implement the Range header, so that the client can skip to a specific position in the file. You can probably find out what goes wrong by sniffing the requestthe player sends.
回答by Martin Holzhauer
What you want is called "Content-Range requests"
你想要的是“内容范围请求”
Have a look here Resumable downloads when using PHP to send the file?
在这里查看使用 PHP 发送文件时的可恢复下载？
回答by Spudley
I came across this recently which may help you:
我最近遇到了这个可能对你有帮助的：
http://www.jasny.net/articles/how-i-php-x-sendfile/
http://www.jasny.net/articles/how-i-php-x-sendfile/
Rather than passing the whole file through PHP (which eats up memory), you can use x-sendfile. This is an Apache module which allows you to run a PHP program, but pass control back to the web server to handle the actual file download once your code has done what it needs to do (authentication, etc).
您可以使用 x-sendfile，而不是通过 PHP 传递整个文件（这会占用内存）。这是一个 Apache 模块，它允许您运行 PHP 程序，但是一旦您的代码完成了它需要做的事情（身份验证等），就会将控制权传递回 Web 服务器来处理实际的文件下载。
It means that your PHP code doesn't have to worry about how the file is served; let the web server do what it's designed for.
这意味着您的 PHP 代码不必担心文件是如何提供的；让网络服务器做它的设计。
Hope that helps.
希望有帮助。
回答by Olical
Here is a good tutorial for it, you only want the PHP section but still: http://www.devshed.com/c/a/PHP/Video-Streaming-PHP-Script-Tutorial/3/
这是一个很好的教程，您只需要 PHP 部分，但仍然需要：http: //www.devshed.com/c/a/PHP/Video-Streaming-PHP-Script-Tutorial/3/
