Javascript 如何使 JSON 数组唯一
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How to make a JSON array unique
提问by coolguy
Possible Duplicate:
Array unique values
Get unique results from JSON array using jQuery
Im having a JSON string like this
我有一个像这样的 JSON 字符串
[
Object { id="38",product="foo"},
Object { id="38",product="foo"},
Object { id="38",product="foo"},
Object { id="39",product="bar"},
Object { id="40",product="hello"},
Object { id="40",product="hello"}
]
There are duplicate values in this JSON array..how can i make this JSON array unique like this
这个 JSON 数组中有重复的值..我怎样才能让这个 JSON 数组像这样独一无二
[
Object { id="38",product="foo"},
Object { id="39",product="bar"},
Object { id="40",product="hello"}
]
.Im looking for a suggestion that uses less iterations,
Jquery $.inArrayis not working in this case.
.我正在寻找使用较少迭代的建议，
Jquery $.inArray在这种情况下不起作用。
Suggestion to use any third party libraries are welcome.
欢迎建议使用任何第三方库。
采纳答案by Flater
Check the solution in the following SO question:
检查以下 SO 问题中的解决方案：
Get unique results from JSON array using jQuery
You'll have to iterate through your array and create a new array which contains unique values.
您必须遍历数组并创建一个包含唯一值的新数组。
回答by Laurent Perrin
You can use underscore's uniq.
您可以使用下划线的 uniq。
In your case, you need to provide an iterator to extract 'id':
在您的情况下，您需要提供一个迭代器来提取“id”：
array = _.uniq(array, true /* array already sorted */, function(item) {
return item.id;
});
回答by Aesthete
// Assuming first that you had **_valid json_**
myList= [
{ "id":"38","product":"foo"},
{ "id":"38","product":"foo"},
{ "id":"38","product":"foo"},
{ "id":"39","product":"bar"},
{ "id":"40","product":"hello"},
{ "id":"40","product":"hello"}
];
// What you're essentially attempting to do is turn this **list of objects** into a **dictionary**.
var newDict = {}
for(var i=0; i<myList.length; i++) {
newDict[myList[i]['id']] = myList[i]['product'];
}
// `newDict` is now:
console.log(newDict);回答by Torsten Walter
You can easily code this yourself. From the top of my head this comes to mind.
您可以轻松地自己编写代码。从我的头顶想到这一点。
var filtered = $.map(originalArray, function(item) {
if (filtered.indexOf(item) <= 0) {
return item;
}
});
Or as suggested a more efficient algorithm specifically for the case at hand:
或者建议一种更有效的算法，专门针对手头的情况：
var helper = {};
var filtered = $.map(originalArray, function(val) {
var id = val.id;
if (!filtered[id]) {
helper[id] = val;
return val;
}
});
helper = null;
回答by SReject
You will probably have to loop through removing the duplicates. If the items stored are in order as you have suggested, it's a simple matter of a single loop:
您可能需要遍历删除重复项。如果存储的项目按照您的建议按顺序排列，则只需一个循环即可：
function removeDuplicates(arrayIn) {
var arrayOut = [];
for (var a=0; a < arrayIn.length; a++) {
if (arrayOut[arrayOut.length-1] != arrayIn[a]) {
arrayOut.push(arrayIn[a]);
}
}
return arrayOut;
}
