java 用多行遍历字符串
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Iterate through String with multiple lines
提问by user1170330
I got some data:
我得到了一些数据：
def data = "# some useless text\n"+
"# even more\n"+
"finally interesting text"
How can I get the "interesting part" of that? So basically all lines, NOT starting with #.
我怎样才能得到它的“有趣的部分”？所以基本上所有行，不以#开头。
回答by tim_yates
One Groovy option would be:
一种 Groovy 选项是：
def data = '''# some useless text
|# even more
|finally interesting text'''.stripMargin()
List lines = data.split( '\n' ).findAll { !it.startsWith( '#' ) }
assert lines == [ 'finally interesting text' ]
回答by user1630753
Use split methodto get substrings then check each one starts with "#" or not. For example:
使用split 方法获取子字符串，然后检查每个子字符串是否以“#”开头。例如：
String[] splitData = data.split("\n");
for (String eachSplit : splitData) {
if (!eachSplit.startWith("#")) {
print(eachSplit);
}
}
回答by jozh
data.eachLine {
if (!it.startsWith( '#' )
println it
}
回答by Riggs
Here is a solution by using Groovy's meta programming feature (http://groovy.codehaus.org/JN3525-MetaClasses):
这是使用 Groovy 的元编程功能 ( http://groovy.codehaus.org/JN3525-MetaClasses)的解决方案：
def data = "# some useless text\n"+
"# even more\n"+
"finally interesting text"
String.metaClass.collectLines = { it ->
delegate.split('\n').findAll it
}
def result = data.collectLines{ !it.startsWith( '#' )}
assert result == ["finally interesting text"]
回答by sradforth
How's about splitting the string with \n character via the split function
如何通过split 函数用 \n 字符拆分字符串
Now you can just test each string if it starts with # or not via String.startsWith("#") .
现在您可以测试每个字符串是否以 # 开头或不通过 String.startsWith("#") .
回答by supersam654
I would split the string based on the newline character (\n) and then ignore the lines that start with "#".
我会根据换行符 (\n) 拆分字符串，然后忽略以“#”开头的行。
String[] lines = data.split("\n");
for (String line : lines) {
if (line.startsWith("#") {
continue;
}
//Do stuff with the important part
}
Note that this is pure Java.
请注意，这是纯Java。
回答by epidemian
A regexp-based solution that does not require to convert the input string into a list is:
不需要将输入字符串转换为列表的基于正则表达式的解决方案是：
def data = '''\
# some useless text
# even more
finally interesting text'''
assert data.replaceAll(/#.*\n/, '') == 'finally interesting text'
If you need to split the input into lines anyways, you can still use regexps if you want to, using the Collection#grepmethod:
如果您仍然需要将输入分成几行，您仍然可以根据需要使用正则表达式，使用以下Collection#grep方法：
assert data.split('\n').grep(~/[^#].*/) == ['finally interesting text']
PS: Regexps FTW! =P
PS：正则表达式 FTW！=P
