ios 无法在 UITableview 中的单元格内单击 UIButton
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can't click UIButton inside a cell in UITableview
提问by Long Neutrals
searched already some possible fixes but all did not solve mine.
已经搜索了一些可能的修复方法，但都没有解决我的问题。
i keep clicking the cell in the uitableview rather than the buttons inside it.
我一直点击 uitableview 中的单元格而不是其中的按钮。
here is my code:
这是我的代码：
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath: (NSIndexPath *)indexPath{
static NSString *CellIdentifier = @"Cell";
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
if (cell == nil) {
cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier];
}
cell.backgroundColor = [UIColor blackColor];
UIView *v = nil;
NSArray *array = [cell subviews];
for (v in array) {
NSLog(@"%@",[v class]);
if( [v isKindOfClass:[UIView class]] ){
[v removeFromSuperview];
}
}
//tb
if (tableView == self.tb) {
v = [[UIView alloc] initWithFrame: CGRectMake(0, 0, self.tb.bounds.size.width, 120.0)];
if([feeds count]>0){
UIImageView *box=[[UIImageView alloc] initWithImage:[UIImage imageNamed:@"statusBox.png"]];
box.userInteractionEnabled = YES;
[v addSubview:box];
AsyncImageView *imageView1 = [[AsyncImageView alloc] initWithFrame:CGRectMake(10, 20.0f, 34.0f, 34.0f)];
imageView1.contentMode = UIViewContentModeScaleAspectFill;
imageView1.clipsToBounds = YES;
//cancel loading previous image for cell
[[AsyncImageLoader sharedLoader] cancelLoadingImagesForTarget:imageView1];
if (users1 != nil && users1.imagelink != nil && (id) users1.imagelink != [NSNull null]){
imageView1.imageURL = [NSURL URLWithString:users1.imagelink];
}
else{
imageView1.image=[UIImage imageNamed:@"default_ProfilePic.png"];
}
UITapGestureRecognizer *tapped = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(myFunction:)];
tapped.numberOfTapsRequired = 1;
[imageView1 addGestureRecognizer:tapped];
[tapped release];
imageView1.userInteractionEnabled = NO;
[v addSubview:imageView1];
UIFont *font = [UIFont fontWithName:@"TrebuchetMS-Bold" size:11];
UILabel *descLabel1 = [[UILabel alloc] initWithFrame: CGRectMake(52, 23, 160, 48)];
descLabel1.text = [NSString stringWithFormat:@"%@ %@",users1.userfirstn,users1.userlastn];
descLabel1.textColor = [UIColor blackColor];
descLabel1.font = font;
descLabel1.adjustsFontSizeToFitWidth=YES;
descLabel1.numberOfLines = 0;
CGSize expectedLabelSize = [descLabel1.text sizeWithFont:descLabel1.font
constrainedToSize:descLabel1.frame.size
lineBreakMode:UILineBreakModeWordWrap];
CGRect newFrame = descLabel1.frame;
newFrame.size.height = expectedLabelSize.height;
descLabel1.frame = newFrame;
descLabel1.numberOfLines = 0;
descLabel1.userInteractionEnabled = NO;
[v addSubview:descLabel1];
UILabel *descLabel2= [[UILabel alloc] initWithFrame: CGRectMake(52, 43, 200, 48)];
StatusClass *stat1=[feeds objectAtIndex:indexPath.row];
descLabel2.text = [stat1 statcreate];
descLabel2.textColor = [UIColor blackColor];
descLabel2.font = font;
descLabel2.adjustsFontSizeToFitWidth=YES;
descLabel2.numberOfLines = 0;
CGSize expectedLabelSize2 = [descLabel2.text sizeWithFont:descLabel2.font
constrainedToSize:descLabel2.frame.size
lineBreakMode:UILineBreakModeWordWrap];
CGRect newFrame2 = descLabel2.frame;
newFrame2.size.height = expectedLabelSize2.height;
descLabel2.frame = newFrame2;
descLabel2.numberOfLines = 0;
descLabel2.userInteractionEnabled = NO;
[v addSubview:descLabel2];
UILabel *descLabel3= [[UILabel alloc] initWithFrame: CGRectMake(10, 63, 280, 80)];
StatusClass *stat=[feeds objectAtIndex:indexPath.row];
descLabel3.text = [stat stattext];
descLabel3.textColor = [UIColor blackColor];
descLabel3.font = font;
descLabel3.adjustsFontSizeToFitWidth=YES;
descLabel3.numberOfLines = 0;
descLabel3.userInteractionEnabled = NO;
[v addSubview:descLabel3];
//comment button
UIButton *buttonC = [UIButton buttonWithType:UIButtonTypeRoundedRect];
[buttonC addTarget:self action:@selector(sendComment:) forControlEvents:UIControlEventTouchUpInside];
[buttonC setImage:[UIImage imageNamed:@"comment.png"] forState:UIControlStateNormal];
buttonC.frame = CGRectMake(2, 160, 145, 35);
buttonC.userInteractionEnabled = YES;
[v addSubview:buttonC];
//share button
UIButton *buttonS = [UIButton buttonWithType:UIButtonTypeRoundedRect];
buttonS.tag = indexPath.row;
[buttonS addTarget:self action:@selector(sendShare:) forControlEvents:UIControlEventTouchUpInside];
[buttonS setImage:[UIImage imageNamed:@"share.png"] forState:UIControlStateNormal];
buttonS.frame = CGRectMake(150, 160, 140, 35);
buttonS.userInteractionEnabled = YES;
[v addSubview:buttonS];
}
v.userInteractionEnabled = YES;
[cell addSubview:v];
}
return cell;
}
I also tried the UITapGestureRecognizerfor the buttons and still not working.
我也尝试了UITapGestureRecognizer按钮，但仍然无法正常工作。
Thanks.
谢谢。
回答by Mateusz266
I'm just baffled by this issue....
我只是被这个问题弄糊涂了......
I managed to fix this problem by doing this on one project:
我通过在一个项目上执行此操作设法解决了这个问题：
func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCellWithIdentifier("RegCell", forIndexPath: indexPath) as! CustomCell
cell.contentView.userInteractionEnabled = false // <<-- the solution
return cell
}
but the same did not work for a different project. I have no idea why...
但同样不适用于不同的项目。我不知道为什么...
回答by Ash
There is another potential cause of problems like this one, and that is UITableViewCellsnow have a contentView. This can and will be placed in front of other views in your custom table view cells in order to pick up touches and detect cell selection. In doing so, it may block touches to any views behind it. I've especially noticed this annoyance when creating cells using nibs.
还有另一个可能导致此类问题的原因，那就是UITableViewCells现在有一个contentView. 这可以并且将被放置在自定义表格视图单元格中的其他视图之前，以便拾取触摸并检测单元格选择。这样做时，它可能会阻止对其背后的任何视图的触摸。在使用笔尖创建单元格时，我特别注意到了这种烦恼。
The accepted means for dealing with this is to ensure that all subviews are added not to the tableview cell itself, but to its contentView. This is a read-only property that adjusts its own frame under certain circumstances, for example when slid sideways to reveal the delete button, or during editing mode. You should therefore ensure that any items you do add to the contentVieware intelligently sized and have the correct resizing behaviour.
处理这个问题的公认方法是确保所有子视图不是添加到 tableview 单元格本身，而是添加到它的contentView. 这是一个只读属性，可在某些情况下调整自己的框架，例如在侧向滑动以显示删除按钮时，或在编辑模式期间。因此，您应该确保添加到 的任何项目contentView都具有智能大小并具有正确的调整大小行为。
Also be aware that by adding cells to the contentView, you may yourself block touches to it and thus prevent the cell from being selected. I personally try not to allow cell selection in tableviews containing cells with custom user-enabled controls. It only leads to confusion and awkward interfaces. In fact, I'm seriously considering replacing all UITableViewsin my future projects with UICollectionViews, which are far more adaptable.
另请注意，通过向 中添加单元格contentView，您自己可能会阻止对其进行触摸，从而防止单元格被选中。我个人尽量不允许在包含具有自定义用户启用控件的单元格的表格视图中选择单元格。它只会导致混乱和尴尬的界面。事实上，我正在认真考虑将UITableViews我未来项目中的所有内容都替换为UICollectionViews，它的适应性要好得多。
-Ash
-灰
回答by Rickye
The UITableViewCell is handling all the gestures by default.
Set cell.selectionStyle = UITableViewCellSelectionStyleNone;to make it disable the default behaviour.
UITableViewCell 默认处理所有手势。设置cell.selectionStyle = UITableViewCellSelectionStyleNone;为禁用默认行为。
回答by HRM
Your UIButton='s y offset is given as 160 and UIView'sheight is just given as 120. Please change the UIButton'sy offset and try.
您的UIButton='sy 偏移量被指定为 160，而UIView's高度仅被指定为 120。请更改UIButton'sy 偏移量并尝试。
回答by Nick
For Swift 3 and Storyboard
对于 Swift 3 和 Storyboard
For me, I had to enable multiple touch inside the content view, and enable user interaction on everything - the table view, table view cell, content view, and UIButton. I was using storyboard.
对我来说，我必须在内容视图中启用多点触控，并在所有内容上启用用户交互 - 表格视图、表格视图单元格、内容视图和 UIButton。我正在使用故事板。
I also set up my tableview cell as a subclass.
我还将我的 tableview 单元格设置为子类。
Since I couldn't find an answer here when I was exploring the problem, I posted another question on stack overflow about this. You can see my code and download a project with this working here: Can't click button inside UITableViewCell?
由于我在探索问题时无法在此处找到答案，因此我在堆栈溢出上发布了另一个关于此问题的问题。你可以在这里查看我的代码并下载一个项目：Can't click button inside UITableViewCell?
回答by Lord Fresh
I was doing this:
我是这样做的：
let plusButton: UIButton = {
let v = UIButton()
v.setImage(plusImg, for: .normal)
v.tintColor = .dark
v.translatesAutoresizingMaskIntoConstraints = false
v.addTarget(self, action: #selector(plusButtonHandler), for: .touchUpInside)
// adding targets here did not work
return v
}()
And it appears invoking the addTarget method inside of the closure did not work. When I factored the addTarget method out and instead put it in the initializer, everything worked!
并且在闭包中调用 addTarget 方法似乎不起作用。当我将 addTarget 方法分解出来并将其放入初始化程序时，一切正常！
回答by ThomasW
I ran into this problem, but in my case it was not related to the table view, instead it was because I was using subviews in my button for which userInteractionEnabledwas true, setting that value for false (NO) for all the button's subviews fixed the issue for me.
我遇到了这个问题，但在我的情况下它与表视图无关，而是因为我在我的按钮中使用了userInteractionEnabled为 true 的子视图，将所有按钮的子视图的值设置为 false (NO) 修复了问题给我。
回答by wj2061
I have the same issue, and somehow I figured out my mistake.
After I changed the constraintswith self(UITableViewCell)to constraintswith contentViewof self(UITableViewCell),my cell's button is clickable again.
我有同样的问题，不知何故我发现了我的错误。
在我将constraintswith更改self(UITableViewCell)为constraintswith contentViewof 后self(UITableViewCell)，我的单元格按钮可以再次点击。
回答by Anil
Create a custom UITableViewCell. Refer this link.
创建自定义 UITableViewCell。请参阅此链接。
Say you have a UIButtonby the name of displayButton, you can do something like this:
假设您有一个UIButton名为 displayButton 的按钮，您可以执行以下操作：
Inside your - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath, after you create your cell,
在您的 内- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath，在您创建单元格之后，
[cell.dislayButton addTarget: self
action: @selector(replyButtonPressed:withEvent:)
forControlEvents: UIControlEventTouchUpInside];
And the create the method like so in your ViewController:
并在您的 ViewController 中像这样创建方法：
- (void) replyButtonPressed: (id) sender withEvent: (UIEvent *) event
{
UITouch * touch = [[event allTouches] anyObject];
CGPoint location = [touch locationInView: self.tableView];
NSIndexPath * indexPath = [self.tableView indexPathForRowAtPoint: location];
}
回答by malex
If you have no alternative selector for the UIButtonpressed inside some UITableViewCellyou need turn off userInteractionEnabledfor the button
如果您没有其他选择器用于UIButton按下某些按钮，则UITableViewCell需要关闭userInteractionEnabled按钮
cellButton.userInteractionEnabled = false
In this case any button touch will propagate to the cell touch.
在这种情况下，任何按钮触摸都会传播到单元格触摸。
