从 Python 中的列表中获取数据范围
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Getting the range of data from a list in Python
提问by Ninja
I have a set of data that is in a list. I am not sure how to make a function which can take the range of that data and return the min and max values in a tuple.
我有一组列表中的数据。我不确定如何创建一个函数，该函数可以获取该数据的范围并返回元组中的最小值和最大值。
data:
数据：
[1,3,4,463,2,3,6,8,9,4,254,6,72]
my code at the moment:
我现在的代码：
def getrange(data):
result=[]
if i,c in data:
range1 = min(data)
range2 = max(data)
result.append(range1, range2)
return result
采纳答案by Austin A
This is a very straight forward question and you're very close. If what I have below isn't correct, then please edit your question to reflect what you would like.
这是一个非常直接的问题，您非常接近。如果我下面的内容不正确，请编辑您的问题以反映您想要的内容。
Try this.
尝试这个。
def minmax(val_list):
min_val = min(val_list)
max_val = max(val_list)
return (min_val, max_val)
Semantics
语义
I have a set of data that is in a list.
我有一组列表中的数据。
Be careful here, you're using python terms in a contradictory manner. In python, there are both sets and lists. I could tell you meant list here but you could confuse people in the future. Remember, in python sets, tuples, and lists are all different from one another.
在这里要小心，你以一种矛盾的方式使用 python 术语。在python中，有集合和列表。我可以告诉你这里的意思是列表，但你将来可能会混淆人们。请记住，在 Python 中，集合、元组和列表都彼此不同。
Here are the differences (taken from BlackHyman's comment below)
以下是差异（摘自下面 BlackHyman 的评论）
Data Type | Immutable | Ordered | Unique Values
===============================================
lists | no | yes | no
tuples | yes | yes | no
sets | no | no | yes
Immutable - the data type can't be changed after instantiation.
不可变 - 实例化后无法更改数据类型。
Ordered - the order of the elements within the data type are persistent.
有序 - 数据类型中元素的顺序是持久的。
Unique Values - the data type cannot have repeated values.
唯一值 - 数据类型不能有重复值。
回答by Falko
I like NumPy's percentilefunction for the ability to get multiple percentiles at once:
我喜欢NumPy 的percentile功能，因为它能够一次获得多个百分位数：
import numpy as np
print np.percentile([1,3,4,463,2,3,6,8,9,4,254,6,72], [0, 100])
Output:
输出：
[ 1. 463.]
(The minimum is the 0 % percentile; and the maximum is the 100 % percentile.)
（最小值为 0 % 百分位数；最大值为 100 % 百分位数。）
If you really need the result in a tuple, you can easily wrap it with tuple(...).
如果你真的需要元组中的结果，你可以很容易地用tuple(...).
回答by Richie Bendall
If You Are Looking To Get The Range Of The Numbers, You Can Use:
如果您想获得数字的范围，您可以使用：
def getrange(numbers):
return max(numbers) - min(numbers)
I've Also Constructed This Code That You Can Use In Finding Averages:
我还构建了此代码，您可以使用它来查找平均值：
def average(numbers, type=None):
import statistics
try:
statistics.mean(numbers)
except:
raise RuntimeError('An Error Has Occured: List Not Specified (0018)')
if type == 'mean':
return statistics.mean(numbers)
elif type == 'mode':
return statistics.mode(numbers)
elif type == 'median':
return statistics.median(numbers)
elif type == 'min':
return min(numbers)
elif type == 'max':
return max(numbers)
elif type == 'range':
return max(numbers) - min(numbers)
elif type == None:
return average(numbers, 'mean')
else:
raise RuntimeError('An Error Has Occured: You Entered An Invalid Operation (0003)')
All You Need To Do Is Type average([1, 2, 3])To Get The Mean Average For 1, 2 And 3. For Other Commands, Do average([1, 2, 3, 'median')And This Will Give The Median Of The Numbers. You Can Change medianto: mean, mode, median, min, maxand range
您需要做的就是键入average([1, 2, 3])以获取 1、2 和 3 的平均平均值。对于其他命令，执行average([1, 2, 3, 'median')此操作将给出数字的中位数。您可以将中位数更改为：mean、mode、median、min、max和range
回答by Sevda
I just did this:
我只是这样做：
>>>data = [1,3,4,463,2,3,6,8,9,4,254,6,72]
>>>min_val = min(data)
>>>max_val = max (data)
>>>range_data = (min_val, max_val)
>>>print(range_data)
(1, 463)
