laravel 合并两个 Eloquent Collections 并删除所有重复项。
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Merge two Eloquent Collections and remove all duplicates.
提问by Rijnhardt
I have two arrays, $user_rolesand $global_roles. I want to make a new array, let's call it $available_roles, where it can be equated as the items in $global_rolesless the items in the $user_roles
我有两个数组，$user_roles和$global_roles. 我想创建一个新数组，我们称之为$available_roles，它可以等同$global_roles于$user_roles
I have the following code to do it to a normal array. $available_roles = array_unique(array_merge($global_roles, $user_roles), SORT_REGULAR);
我有以下代码可以对普通数组执行此操作。 $available_roles = array_unique(array_merge($global_roles, $user_roles), SORT_REGULAR);
This is proving to be problematic due to the fact that Laravel does not use traditional arrays when one executes a query, it uses Eloquent Collections.
这被证明是有问题的，因为 Laravel 在执行查询时不使用传统数组，而是使用 Eloquent 集合。
What other ideas do you guys have?
大家还有什么想法？
回答by lukasgeiter
This is fairly simple. You can use the Collection's mergemethod:
这相当简单。您可以使用集合的merge方法：
$available_roles = $global_roles->merge($user_roles);
Because mergeinternally uses an associative array (dictionary) that uses the id as key, this should automatically remove duplicates.
因为在merge内部使用一个关联数组（字典），它使用 id 作为键，这应该会自动删除重复项。
Anyways though, you can remove duplicates in a collection using unique:
无论如何，您可以使用unique以下方法删除集合中的重复项：
$uniqueCollection = $collection->unique();
Now that was for mergingwhat you're actually are looking for is the differencebetween two collections. You can do this in two ways:
现在这是为了合并您实际要寻找的两个集合之间的差异。您可以通过两种方式执行此操作：
$available_roles = $user_roles->diff($global_roles);
or
或者
$available_roles = $global_roles->except($user_roles->modelKeys());
