Ruby-on-rails link_to :action => 'create' 去索引而不是 'create'
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link_to :action => 'create' going to index rather than 'create'
提问by pedalpete
I am building a fairly simple recipe app to learn RoR, and I am attempting to allow a user to save a recipe by clicking a link rather than through a form, so I am connecting the user_recipe controllers 'create' function through a link_to.
我正在构建一个相当简单的配方应用程序来学习 RoR，并且我试图允许用户通过单击链接而不是通过表单来保存配方，因此我通过 link_to 连接 user_recipe 控制器“创建”功能。
Unfortunately, for some reason the link_to is calling the index function rather than the create.
不幸的是，由于某种原因，link_to 调用的是索引函数而不是创建函数。
I've written the link_to as
我已经将 link_to 写为
<%= "save this recipe", :action => 'create', :recipe_id => @recipe %>
this link is on the user_recipes/index.html.erb and is calling the 'create' function of the same controller. It doesn't seem to make a difference if I include the :controller or not.
此链接位于 user_recipes/index.html.erb 上，正在调用同一控制器的“创建”功能。如果我包含 :controller 似乎没有什么区别。
The controllers look like this
控制器看起来像这样
def index
@recipe = params[:recipe_id]
@user_recipes = UserRecipes.all # change to find when more than one user in db
respond_to do |format|
format.html #index.html.erb
format.xml { render :xml => @recipes }
end
end
def create
@user_recipe = UserRecipe.new
@user_recipe.recipe_id = params[:recipe_id]
@user_recipe.user_id = current_user
respond_to do |format|
if @menu_recipe.save
format.html { redirect_to(r, :notice => 'Menu was successfully created.') }
format.xml { render :xml => @menu, :status => :created, :location => @menu }
else
format.html { render :action => "new" }
format.xml { render :xml => @menu.errors, :status => :unprocessable_entity }
end
end
回答by sepp2k
In the standard REST scheme the index action and the create action both have the same url (/recipes) and only differ in that index is accessed using GET and create is accessed using POST. So link_to :action => :createwill simply generate a link to /recipeswhich will cause the browser to perform a GET request for /recipeswhen clicked and thus invoke the index action.
在标准的 REST 方案中，索引操作和创建操作都具有相同的 url ( /recipes)，唯一的不同在于索引是使用 GET 访问的，而创建是使用 POST 访问的。Solink_to :action => :create将简单地生成一个链接，/recipes该链接将导致浏览器/recipes在单击时执行 GET 请求，从而调用索引操作。
To invoke the create action use link_to {:action => :create}, :method => :post, telling link_toexplicitly that you want a post request, or use a form with a submit button rather than a link.
要调用 create 操作，请使用link_to {:action => :create}, :method => :post，link_to明确告知您想要发布请求，或使用带有提交按钮而不是链接的表单。
回答by Yusuf Saber
Assuming you have default resources set up in your routes file, i.e. something like this
假设您在路由文件中设置了默认资源，即像这样
resources :recipes
The following will generate a link that will create a recipe; i.e. will be routed to the create action.
以下将生成将创建配方的链接；即将被路由到创建操作。
<%= link_to "Create Recipe", recipes_path, :method => :post %>
For this to work, JS needs to be enabled in your browser.
为此，需要在浏览器中启用 JS。
The following will generate a link that will show all recipes; i.e. will be routed to the index action.
以下将生成一个显示所有食谱的链接；即将被路由到索引操作。
<%= link_to "All Recipes", recipes_path %>
This assumes the default which is a Get HTTP request.
这假定默认值为 Get HTTP 请求。
