java 正则表达式匹配单词，后跟零个或多个数字？
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Regex to match word, followed by zero or more digits?
提问by kofucii
I need a regular expression to match line beginning with a specific WORD, followed by zero or more digits, then nothing more. So far I've tried this:
我需要一个正则表达式来匹配以特定 开头的行WORD，后跟零个或多个数字，然后仅此而已。到目前为止，我已经尝试过这个：
^WORD\d{0,}
and this:
还有这个：
^WORD[0-9]*
But it doesn't work as expected: it is also matching lines like WORD11a, which I don't want.
但它没有按预期工作：它也匹配像 那样的行WORD11a，这是我不想要的。
回答by kofucii
I forgot the $end of line character, so it matched:
我忘记了$行尾字符，所以它匹配：
WORD1
WORD11
WORD11a
this works, just fine:
这有效，就好了：
^WORD\d*$
回答by aioobe
The problem is probably that ^matches the beginning of the input (I suspect you only find a match if the first line matches), and not the beginning of a line.
问题可能是^匹配输入的开头（我怀疑你只在第一行匹配时才找到匹配项），而不是一行的开头。
You could try using a positive lookbehind saying that the match should be preceded by either start of input (^) or a new line (\n):
您可以尝试使用积极的lookbehind 说匹配应该以输入开头 ( ^) 或新行 ( \n)开头：
String input = "hello156\n"+
"world\n" +
"hello\n" +
"hell55\n";
Pattern p = Pattern.compile("(?<=^|\n)hello\d*");
Matcher m = p.matcher(input);
while (m.find())
System.out.println("\"" + m.group() + "\"");
Prints:
印刷：
"hello156"
"hello"
回答by user3841723
"(\\AWORD[\\d]*$)" this should do the trick. beginning of input, your WORD, and a number
"(\\AWORD[\\d]*$)" 这应该可以解决问题。输入的开头、你的 WORD 和一个数字
