pandas 值之间的熊猫系列过滤
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pandas series filtering between values
提问by Jason S
If sis a pandas.Series, I know I can do this:
如果s是 a pandas.Series，我知道我可以这样做：
b = s < 4
or
或者
b = s > 0
but I can't do
但我做不到
b = 0 < s < 4
or
或者
b = (0 < s) and (s < 4)
What is the idiomatic pandas method for creating a boolean series based on the logical AND / OR / NOT of other boolean series?
基于其他布尔系列的逻辑 AND / OR / NOT 创建布尔系列的惯用Pandas方法是什么？
采纳答案by Jason S
found it... the &operator works, but you need to use parentheses to get the precedence right and avoid an error:
找到了...&运算符有效，但您需要使用括号来获得正确的优先级并避免错误：
>>> import pandas as pd
>>> s1 = pd.Series([0,1,2,3,4,5,6,0,1,2,3,4])
>>> (s1 < 4) & (s1 > 0)
0 False
1 True
2 True
3 True
4 False
5 False
6 False
7 False
8 True
9 True
10 True
11 False
dtype: bool
>>> s1 < 4 & s1 > 0
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "c:\app\python\anaconda.6.0\lib\site-packages\pandas\core\generic.py",
line 698, in __nonzero__
.format(self.__class__.__name__))
ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().
回答by fantabolous
You can also use .between:
您还可以使用.between：
s1.between(0, 4, inclusive=False)
A bit verbose but as it doesn't have to create 2 intermediary series it should be faster (admittedly untested).
有点冗长，但因为它不必创建 2 个中间系列，所以它应该更快（诚然未经测试）。
