Bash 命令对一列数字求和
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/3096259/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Bash command to sum a column of numbers
提问by Jubal
I want a bash command that I can pipe into that will sum a column of numbers. I just want a quick one liner that will do something essentially like this:
我想要一个 bash 命令，我可以通过管道输入它来对一列数字求和。我只想要一个快速的班轮，基本上可以做这样的事情：
cat FileWithColumnOfNumbers.txt | sum
回答by Dimitre Radoulov
Using existing file:
使用现有文件：
paste -sd+ infile | bc
Using stdin:
使用标准输入：
<cmd> | paste -sd+ | bc
Edit: With some pasteimplementations you need to be more explicit when reading from stdin:
编辑：使用一些粘贴实现，从stdin读取时需要更加明确：
<cmd> | paste -sd+ - | bc
<cmd> | paste -sd+ - | bc
回答by ghostdog74
I like the chosen answer. However, it tends to be slower than awk since 2 tools are needed to do the job.
我喜欢选择的答案。然而，它往往比 awk 慢，因为需要 2 个工具来完成这项工作。
$ wc -l file
49999998 file
$ time paste -sd+ file | bc
1448700364
real 1m36.960s
user 1m24.515s
sys 0m1.772s
$ time awk '{s+=}END{print s}' file
1448700364
real 0m45.476s
user 0m40.756s
sys 0m0.287s
回答by Jonathan Leffler
Does two lines count?
两行算不算？
awk '{ sum += ; }
END { print sum; }' "$@"
You can then use it without the superfluous 'cat':
然后，您可以在没有多余的“猫”的情况下使用它：
sum < FileWithColumnOfNumbers.txt
sum FileWithColumnOfNumbers.txt
FWIW: on MacOS X, you can do it with a one-liner:
FWIW：在 MacOS X 上，您可以使用 one-liner：
awk '{ sum += ; } END { print sum; }' "$@"
回答by minhas23
The following command will add all the lines(first field of the awk output)
以下命令将添加所有行（awk 输出的第一个字段）
awk '{s+=} END {print s}' filename
回答by Dimitre Radoulov
[a followup to ghostdog74s comments]
[ghostdog74s评论的后续]
bash-2.03$ uname -sr
SunOS 5.8
bash-2.03$ perl -le 'print for 1..49999998' > infile
bash-2.03$ wc -l infile
49999998 infile
bash-2.03$ time paste -sd+ infile | bc
bundling space exceeded on line 1, teletype
Broken Pipe
real 0m0.062s
user 0m0.010s
sys 0m0.010s
bash-2.03$ time nawk '{s+=}END{print s}' infile
1249999925000001
real 2m0.042s
user 1m59.220s
sys 0m0.590s
bash-2.03$ time /usr/xpg4/bin/awk '{s+=}END{print s}' infile
1249999925000001
real 2m27.260s
user 2m26.230s
sys 0m0.660s
bash-2.03$ time perl -nle'
$s += $_; END { print $s }
' infile
1.249999925e+15
real 1m34.663s
user 1m33.710s
sys 0m0.650s
回答by DVK
You can use bc (calculator). Assuming your file with #s is called "n":
您可以使用 bc（计算器）。假设带有#s 的文件称为“n”：
$ cat n
1
2
3
$ (cat n | tr "2" "+" ; echo "0") | bc
6
The trchanges all newlines to "+"; then we append 0 after the last plus, then we pipe the expression (1+2+3+0) to the calculator
将tr所有换行符更改为“+”；然后我们在最后一个加号后附加 0，然后我们将表达式 ( 1+2+3+0) 通过管道传输到计算器
Or, if you are OK with using awk or perl, here's a Perl one-liner:
或者，如果您可以使用 awk 或 perl，这里有一个 Perl 单行：
$perl -nle '$sum += $_ } END { print $sum' n
6
回答by Paused until further notice.
while read -r num; do ((sum += num)); done < inputfile; echo $sum
回答by t6d
Use a forloop to iterate over your file …
使用for循环遍历您的文件……
sum=0; for x in `cat <your-file>`; do let sum+=x; done; echo $sum
回答by Joe Cannatti
If you have ruby installed
如果你安装了 ruby
cat FileWithColumnOfNumbers.txt | xargs ruby -e "puts ARGV.map(&:to_i).inject(&:+)"
回答by paco
[root@pentest3r ~]# (find / -xdev -size +1024M) | (while read a ; do aa=$(du -sh $a | cut -d "." -f1 ); o=$(( $o+$aa )); done; echo "$o";)
