C++ 内联数组初始化
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Inline array initialization
提问by Gzorg
I was used to using
我习惯使用
new int[] {1,2,3,4,5};
for initializing array. But it seems nowadays, this does not work anymore, i have to explicitly state how many elements there are, with
用于初始化数组。但现在看来，这不再有效，我必须明确说明有多少元素，
new int[5] {1,2,3,4,5};
so compilers forgot how to count ?
所以编译器忘记了如何计数？
And to make this a closed question, is there a way to omit the number of elements ?
为了使这是一个封闭的问题，有没有办法省略元素的数量？
回答by CB Bailey
This has never worked in the current version of C++, you have only been able to zero-initialize(or not initialize) dynamically allocated arrays.
这在当前版本的 C++ 中从未奏效，您只能对动态分配的数组进行零初始化（或不初始化）。
What has always worked is non-dynamically allocated array initialization:
一直有效的是非动态分配的数组初始化：
int myarray[] = {1, 2, 3, 4, 5};
Perhaps you are confusing it with this?
也许你把它与这个混淆了？
Even in C++0x it is not legal syntax to omit the explicit array size specifier in a new expression.
即使在 C++0x 中，在 new 表达式中省略显式数组大小说明符也是不合法的语法。
回答by Oleg Danu
C++ have never allowed to initialize array with an unknown size of elements like above. The only 2 ways I know, is specify the number of elements or use pointers.
C++ 从未允许使用上述未知大小的元素初始化数组。我知道的唯一两种方法是指定元素的数量或使用指针。
