php 从 $_POST 中的 json 读取关联数组
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Read associative array from json in $_POST
提问by Daniel
I am using jQuery to post a json object to my php application.
我正在使用 jQuery 将 json 对象发布到我的 php 应用程序。
jQuery.post("save.php",JSON.stringify(dataToSend), function(data){ alert(data); });
The json string as pulled from firebug looks like this
从 firebug 中提取的 json 字符串如下所示
{ "data" : [ { "contents" : "This is some content",
"selector" : "DIV.subhead"
},
{ "contents" : "some other content",
"selector" : "LI:nth-child(1) A"
}
],
"page" : "about_us.php"
}
In php I am trying to turn this into an associative array.
在 php 我试图把它变成一个关联数组。
My php code so far is
到目前为止，我的 php 代码是
<?php
$value = json_decode(stripcslashes($_POST));
echo $value['page'];
?>
The response to the ajax call should be "about_us.php" but it comes back blank.
对 ajax 调用的响应应该是“about_us.php”，但它返回空白。
采纳答案by Francesco Terenzani
You can avoid to use JSON.stringifyand json_decode:
您可以避免使用JSON.stringify和json_decode：
jQuery.post("save.php", dataToSend, function(data){ alert(data); });
And:
和：
<?php
echo $_POST['page'];
?>
Update:
更新：
... but if your really want to use them, then:
...但如果你真的想使用它们，那么：
jQuery.post("save.php", {json: JSON.stringify(dataToSend)}, function(data){ alert(data); });
And:
和：
<?php
$value = json_decode($_POST['json']);
echo $value->page;
?>
回答by Evert
$_POSTwill not be populated if the request body is not in the standard urlencoded form.
$_POST如果请求正文不是标准的 urlencoded 形式，则不会填充。
Instead, read from the read-only php://inputstreamlike this to get the raw request body:
相反，像这样从只读php://input流中读取以获取原始请求正文：
$value = json_decode(file_get_contents('php://input'));
回答by Shakti Singh
Pass the second argument as true if you want the associative array otherwise it will keep returning object.
如果您想要关联数组，则将第二个参数传递为 true，否则它将继续返回对象。
$value = json_decode(stripslashes($_POST),true);
回答by Paul DelRe
It looks like jQuery might encode a javascript object in urlencoded form then would be populated into $_POST. At least from their examples. I'd try passing in your object into post()without stringifying it.
看起来 jQuery 可能会以 urlencoded 形式对 javascript 对象进行编码，然后将填充到 $_POST 中。至少从他们的例子来看。我会尝试将您的对象传入post()而不对其进行字符串化。
回答by karim79
Try:
尝试：
echo $value->page;
since json_decode's default behaviour is to return an object of type stdClass.
因为json_decode的默认行为是返回一个类型的对象stdClass。
Alternatively, set the second optional $assocargument to true:
或者，将第二个可选$assoc参数设置为true：
$value = json_decode(stripslashes($_POST), true);
echo $value['page'];
回答by Mukesh
If you want to use json data as an associative array, you can try as following:
如果你想使用 json 数据作为关联数组，你可以尝试如下：
<?php
$json = 'json_data'; // json data
$obj = jsondecode($json, true); // decode json as associative array
// now you can use different values as
echo $obj['json_string']; // will print page value as 'about_us.php'
for example:
$json = { "data" : [ { "contents" : "This is some content",
"selector" : "DIV.subhead"
},
{ "contents" : "some other content",
"selector" : "LI:nth-child(1) A"
}
],
"page" : "about_us.php"
}
$obj = json_decode($json, true);
/* now to print contents from data */
echo $obj['data']['contents'];
// thats all
?>
