bash 在浮点bash printf上填充零
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padding zero on floating point bash printf
提问by lev.tuby
I would like to have a floating point number printed in bash with padded zeroes to fill a range %5.3f. I know of printf function.
我想在 bash 中打印一个带有填充零的浮点数来填充范围 %5.3f。我知道 printf 函数。
My problem is the following:
我的问题如下：
printf "0%5.3f\n" 3.00
returns, as expected,
正如预期的那样返回，
03.000
but the line
但这条线
printf "0%5.3f\n" 23.00
gives instead
给
023.000
which is not what I want of course.
这当然不是我想要的。
Any suggestion?
有什么建议吗？
回答by Michael Wild
You have to put the 0afterthe %:
你必须把0之后的%：
printf "%06.3f\n" 23.00
Notice that I also increased the minimum field width to 6, otherwise no padding will occur (3 decimal places, one dot, leaves just a single digit in front of the decimal point).
请注意，我还将最小字段宽度增加到 6，否则不会出现填充（3 个小数位，一个点，在小数点前只留下一个数字）。
回答by Axel
If anything at all, the 0 would have to be on the right side of the percent sign. I don't have a linux system at work, but try printf "%05.3f\n" 23.00.
如果有的话，0 必须在百分号的右侧。我没有在工作的 linux 系统，但试试printf "%05.3f\n" 23.00.
