Jquery 拖放和克隆
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/2100896/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Jquery drag /drop and clone
提问by Sajeev
Hi I need to achive this ..
嗨，我需要达到这个..
I have a set of droppable items ( basically I am droping designs on a apparel ) and I am dropping a clone..
我有一套可放置的物品（基本上我是在服装上放置设计）并且我正在放置一个克隆..
If I don't like the dropped object (designs) - I want to delete that by doing something like hidden .
如果我不喜欢丢弃的对象（设计）- 我想通过执行 hidden 之类的操作来删除它。
But I am unable to do that.
但我无法做到这一点。
Please help me..
请帮我..
here is the code
这是代码
var clone;
$(document).ready(function(){
$(".items").draggable({helper: 'clone',cursor: 'hand'});
$(".droparea").droppable({
accept: ".items",
hoverClass: 'dropareahover',
tolerance: 'pointer',
drop: function(ev, ui)
{
var dropElemId = ui.draggable.attr("id");
var dropElem = ui.draggable.html();
clone = $(dropElem).clone(); // clone it and hold onto the jquery object
clone.id="newId";
clone.css("position", "absolute");
clone.css("top", ui.absolutePosition.top);
clone.css("left", ui.absolutePosition.left);
clone.draggable({ containment: 'parent' ,cursor: 'crosshair'});
$(this).append(clone);
alert("done dragging ");
/lets assume I have a delete button when I click that clone should dissapear so that I can drop another design - but the following code has no effect
//and the item is still visible , how to make it dissapear ?
$('#newId').css("visibility","hidden");
}
});
});
回答by fredrik
Since .clone() returns a jQuery object. clone.id="newId" sets an property on the jQuery object not the DOM element. Since the DOM element doesn't have an id property. $('#newId').length should return null. Test in firebug console
由于 .clone() 返回一个 jQuery 对象。clone.id="newId" 在 jQuery 对象而不是 DOM 元素上设置一个属性。由于 DOM 元素没有 id 属性。$('#newId').length 应该返回 null。在萤火虫控制台中测试
Use:
用：
clone.attr('id', 'newId')
to set an ID on the cloned object's DOM element.
在克隆对象的 DOM 元素上设置 ID。
回答by There is a dream I am living T
You can use drop dragabble object function:
您可以使用拖放对象功能：
drop: function (event, ui) {
$(ui.draggable).remove();
}
after
后
$(this).append(clone);
in your script;
在你的脚本中；
