java Spring AOP - 每个带有注释的方法的切入点
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/7817822/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Spring AOP - pointcut for every method with an annotation
提问by emesx
I am trying to define a pointcut, that would catch every method that is annotated with (i.e.) @CatchThis. This is my own annotation.
我正在尝试定义一个切入点，它将捕获每个用 (ie) 注释的方法@CatchThis。这是我自己的注释。
Moreover, I'd like to have access to the first argument of the method, which will be of Longtype. There may be other arguments too, but I don't care about them.
此外，我想访问该方法的第一个参数，该参数的Long类型。可能还有其他争论，但我不在乎。
EDIT
编辑
This is what I have right now. What I don't know is how to pass the first parameter of the method annotated with @CatchThis.
这就是我现在所拥有的。我不知道的是如何传递带有注释的方法的第一个参数@CatchThis。
@Aspect
public class MyAspect {
@Pointcut(value = "execution(public * *(..))")
public void anyPublicMethod() {
}
@Around("anyPublicMethod() && @annotation(catchThis)")
public Object logAction(ProceedingJoinPoint pjp, CatchThis catchThis) throws Throwable {
return pjp.proceed();
}
}
回答by Sean Patrick Floyd
Something like this should do:
这样的事情应该做：
@Aspect
public class MyAspect{
@Pointcut(value="execution(public * *(..))")
public void anyPublicMethod() {
}
@Around("anyPublicMethod() && @annotation(catchThis) && args(.., Long ,..)")
public Object logAction(
ProceedingJoinPoint pjp, CatchThis catchThis, Long long)
throws Throwable {
return pjp.proceed();
}
}
