php 递归 chmod/chown/chgrp 目录中的所有文件和文件夹
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Recursively chmod/chown/chgrp all files and folder within a directory
提问by Steve Robbins
I am working on a site which builds other sites. Some if it I use copy()to create the files and directories, other times I'm building XML files in php and using DOMDocument::saveto save them. The end result is a root folder with all sorts of messed up permissions. I've beening modding files and folders as I go, which words to some extent, but I'm particularly having trouble when it comes to using copy().
我正在一个建立其他网站的网站上工作。有些时候我使用copy()创建文件和目录，其他时候我在 php 中构建 XML 文件并使用DOMDocument::save来保存它们。最终结果是一个具有各种混乱权限的根文件夹。我一直在修改文件和文件夹，这在某种程度上说，但在使用copy().
(This is where I'm at so far http://pastebin.com/SBE8vtFX, attn: function modPath($path))
（这是我在哪里至今http://pastebin.com/SBE8vtFX，经办人：function modPath($path)）
I want to take a different approach and recursively chmod/chown/chgrpall the files and folders within my document root to my specifications at once.
我要采取不同的方法和递归CHMOD / CHOWN / chgrp命令所有的我的文档根目录中的文件和文件夹到我的规格一次。
Take for example the document root
以文档根目录为例
/home/mysite/public_html
and within public_htmlI have
并在public_html我
-rwxrwxrwx 1 mysite mysite 348 Aug 31 10:49 index.php
d--------x 5 root root 4096 Aug 30 10:21 folder1
drwxrwxrwx 2 mysite mysite 4096 Aug 30 09:41 folder2
My question:
我的问题：
How can I mod allfiles within a specified directory at once? I want to differentiate different chmod settings between directories and folders as well. This needs to be a PHP solution.
如何一次修改指定目录中的所有文件？我也想区分目录和文件夹之间的不同 chmod 设置。这需要是一个 PHP 解决方案。
This is as far as I can get
这是我所能得到的
<?php
function modAll($root) {
$aPath = explode("/", $root);
$user = $aPath[2];
/* Some sort of looping through $root */ {
$mod = (is_dir($thisfileorfolder) ? 0755 : 0644);
chmod($thisfileorfolder, $mod);
chown($thisfileorfolder, $user);
chgrp($thisfileorfolder, $user);
}
}
?>
回答by Felipe Buccioni
This should be helpful. EDITED: some syntax errors corrected
这应该会有所帮助。已编辑：更正了一些语法错误
function fsmodify($obj) {
$chunks = explode('/', $obj);
chmod($obj, is_dir($obj) ? 0755 : 0644);
chown($obj, $chunks[2]);
chgrp($obj, $chunks[2]);
}
function fsmodifyr($dir)
{
if($objs = glob($dir."/*")) {
foreach($objs as $obj) {
fsmodify($obj);
if(is_dir($obj)) fsmodifyr($obj);
}
}
return fsmodify($dir);
}
回答by rouzier
回答by Joshua
system("/bin/chmod -R $mod $root");
system("/usr/bin/find -type d $root -print0 | xargs -0 | /bin/chmod $moddir");
system("/bin/chown -R $user $root");
system("/bin/chgrp -R $user $root");
Invalid mode 493 means you passed your mode as decimal. Convert to octal string first.
无效模式 493 表示您以十进制形式传递了您的模式。首先转换为八进制字符串。
