php preg_replace 所有空格
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preg_replace all spaces
提问by user740521
I'm trying to replace all spaces with underscores and the following is not working:
我正在尝试用下划线替换所有空格，但以下内容不起作用：
$id = "aa aa";
echo $id;
preg_replace('/\s+/', '_', $id);
echo $id;
prints
印刷
aa aaaa aa
回答by Mark Byers
The function preg_replacedoesn't modify the string in-place. It returns a new string with the result of the replacement. You should assign the result of the call back to the $idvariable:
该函数preg_replace不会就地修改字符串。它返回一个带有替换结果的新字符串。您应该将回调的结果分配给$id变量：
$id = preg_replace('/\s+/', '_', $id);
回答by Clive
I think str_replace()might be more appropriate here:
我认为str_replace()这里可能更合适：
$id = "aa aa";
$id = str_replace(' ', '_', $id);
echo $id;
回答by Martin.
You have forgotten to assign the result of preg_replaceinto your $id
您忘记将结果分配preg_replace到您的$id
$id = preg_replace('/\s+/', '_', $id);
回答by Mahesh Mohan
Sometimes, in linux/unix environment,
有时，在 linux/unix 环境中，
$strippedId = preg_replace('/\h/u', '', $id);
Try this as well.
也试试这个。
回答by web_developer
We need to replace the space in the string "aa aa" with '_' (underscore). The \s+ is used to match multiple spaces. The output will be "aa_aa"
我们需要用'_'（下划线）替换字符串“aa aa”中的空格。\s+ 用于匹配多个空格。输出将是“aa_aa”
<?php
$id = "aa aa";
$new_id = preg_replace('/\s+/', '_', $id);
echo $new_id;
?>
