spring 特定日期的 Cron 表达式
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Cron expression for particular date
提问by paxdiablo
I want a cron expression that represents 6th September 2010 6:00 am
我想要一个代表 2010 年 9 月 6 日上午 6:00 的 cron 表达式
回答by paxdiablo
Original question was tagged cronso this first section applies to that. See below for an updated answer for the Quartz CronTrigger tool.
原始问题已标记，cron因此第一部分适用于此。有关 Quartz CronTrigger 工具的更新答案，请参见下文。
Most crontabs don't let you specify the year so you'll probably have to put that in the script itself (or a wrapper around the script/program).
大多数 crontab 不允许您指定年份，因此您可能必须将其放入脚本本身（或脚本/程序的包装器）中。
You can do this with something like:
您可以使用以下方法执行此操作：
if [[ $(date +%Y) != 2010 ]] ; then
exit
fi
The option you're looking for to run at 6am on September 6 everyyear is
您正在寻找在每年9 月 6 日早上 6 点运行的选项是
0 6 6 9 * your_command_goes_here
| | | | |
| | | | +- any day of the week.
| | | +--- 9th month (September).
| | +----- 6th day of the month.
| +------- 6th hour of the day.
+--------- Top of the hour (minutes = 0).
For the Quartz CronTrigger format, you'd be looking at something like:
对于 Quartz CronTrigger 格式，您会看到如下内容：
0 0 6 6 9 ? 2010
| | | | | | |
| | | | | | +- 2010 only.
| | | | | +----- any day of the week.
| | | | +------- 9th month (September).
| | | +--------- 6th day of the month.
| | +----------- 6th hour of the day.
| +------------- Top of the hour (minutes = 0).
+--------------- Top of the minute (seconds = 0).
(details garnered from here).
（从这里获得的详细信息）。
回答by tbalazs
回答by PajaS
It could be only in /etc/crontab by follows:
它只能在 /etc/crontab 中，如下所示：
0 6 6 9 * root test `/bin/date +%Y` == 2010 && <your command>
