JavaScript 正则表达式：查找非数字字符
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JavaScript regex: find non-numeric character
提问by JamesBrownIsDead
Let's say I have these two strings: "5/15/1983" and "1983.05.15". Assume that all characters in the string will be numeric, except a "separator" character that can appear anywhere in the string. There will be only one separator character; all instances of any given non-numeric character in the string will be identical.
假设我有这两个字符串：“5/15/1983”和“1983.05.15”。假设字符串中的所有字符都是数字，除了可以出现在字符串中任何位置的“分隔符”字符。将只有一个分隔符；字符串中任何给定非数字字符的所有实例都是相同的。
How can I use regex to extract this character? Is there a more efficient way than the one below?
如何使用正则表达式来提取这个字符？有没有比下面更有效的方法？
"05-15-1983".replace(/\d/g, "")[0];
Thanks!
谢谢！
回答by Matthew Flaschen
"05-15-1983".match(/\D/)
Technically, this returns an array containing one string, but it will implicitly convert to the string most places you need this.
从技术上讲，这将返回一个包含一个字符串的数组，但它会在您需要的大多数地方隐式转换为字符串。
回答by KoolKabin
Though i could not exactly get what you trying to do i tried to extract the numbers only in one string and the seperator in next string.
虽然我不能完全得到你想要做什么，但我试图只提取一个字符串中的数字和下一个字符串中的分隔符。
I used the above:
我使用了上面的：
<script>
var myStr1 = "1981-01-05";
var myStr2 = "1981-01-05";
var RegEx1 = /[0-9]/g;
var RegEx2 = /[^0-9]/g;
var RegEx3 = /[^0-9]/;
document.write( 'First : ' + myStr1.match( RegEx1 ) + '<br />' );
document.write( 'tooo : ' + myStr2.replace( RegEx2, "" ) + '<br />' );
document.write( 'Second : ' + myStr1.match( RegEx2 ) + '<br />' );
document.write( 'Third : ' + myStr1.match( RegEx3 ) + '<br />' );
</script>
Output:
输出：
First : 1,9,8,1,0,1,0,5
tooo : 19810105
Second : -,-
Third : -
I hope you get your answer
我希望你得到你的答案
回答by eldarerathis
Clearly tired or not paying attention on my previous answer. Sorry about that. What I shouldhave written was:
显然累了或没有注意我之前的回答。对于那个很抱歉。我应该写的是：
var regexp = new RegExp("([^0-9])","g");
var separator = regexp.exec("1985-10-20")[1];
Of course, Matthew Flaschen's works just as well. I just wanted to correct mine.
当然，Matthew Flaschen 的作品也一样。我只是想纠正我的。
