Python 为什么列表索引必须是整数，而不是元组？
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Why list indices must be integers, not tuple?
提问by Roman
I have this simple program:
我有这个简单的程序：
x = {}
x[1,2] = 3
print x
print x[1,2]
It works fine. The fist printgenerates {(1,2):3}and the second one generates 3.
它工作正常。拳头print生成{(1,2):3}，第二个生成3。
But in my "big" program I seems to do the same but get a list indices must be integers, not tupleerror. What this error message can mean and how I can resolve this problem?
但是在我的“大”程序中，我似乎也做了同样的事情，但出现了list indices must be integers, not tuple错误。此错误消息可能意味着什么以及如何解决此问题？
采纳答案by unwind
If you're getting that error, then you are trying to index a list, and not a dictionary.
如果您收到该错误，那么您正在尝试索引一个列表，而不是一个字典。
A Python list, like [1, 2, 3], must be indexed with integer values. A dictionary, which is what you have in your example, can be indexed by a wider range of different values.
Python 列表，如[1, 2, 3]，必须使用整数值进行索引。您在示例中拥有的字典可以通过更广泛的不同值进行索引。
回答by Andrew Jaffe
Note that x={}defines xto be a dictionary, not a list (which can have any hashable as a key, and with syntactic sugar that translates d[key1,key2]to d[(key1,key2)]).
请注意，x={}定义x是一个字典，而不是一个列表（它可以有任何可散列的作为键，并带有转换d[key1,key2]为 的语法糖d[(key1,key2)]）。
See, however, numpy, which allows multidimensional arrays if that's really what you want.
但是，请参阅numpy，如果这确实是您想要的，它允许多维数组。
回答by lightning2911
x = {}
This creates a dictionary, not a list.
这将创建一个字典，而不是一个列表。
x[1,2] = 3
assigns the value 3 to the key (1, 2) a tuple.
将值 3 赋给键 (1, 2) 一个元组。
A list can only be indexed by integers. Maybe you have mixed up the [] und {} using your dict?
列表只能由整数索引。也许您使用字典混淆了 [] 和 {}？
