C#中的四舍五入十进制值
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Round Off decimal values in C#
提问by Guddu
how do i round off decimal values ?
Example :
我如何舍入十进制值？
例子 ：
decimal Value = " 19500.98"
十进制值 =“19500.98”
i need to display this value to textbox with rounded off like " 19501 "
我需要将此值显示到文本框，四舍五入，如“19501”
if decimal value = " 19500.43"
如果十进制值 = " 19500.43"
then
然后
value = " 19500 "
值 = " 19500 "
采纳答案by Jon Skeet
Look at Math.Round(decimal)or the overload which takes a MidpointRoundingargument.
看看Math.Round(decimal)或带MidpointRounding参数的重载。
Of course, you'll need to parse and format the value to get it from/to text. If this is input entered by the user, you should probably use decimal.TryParse, using the return value to determine whether or not the input was valid.
当然，您需要解析和格式化该值以从/到文本获取它。如果这是用户输入的输入，您可能应该使用decimal.TryParse，使用返回值来确定输入是否有效。
string text = "19500.55";
decimal value;
if (decimal.TryParse(text, out value))
{
value = Math.Round(value);
text = value.ToString();
// Do something with the new text value
}
else
{
// Tell the user their input is invalid
}
回答by Paul Alexander
Math.Round( value, 0 )
Math.Round( 值, 0 )
回答by NinethSense
d = decimal.Round(d);
回答by Manish Basantani
Try this...
尝试这个...
var someValue=123123.234324243m;
var strValue=someValue.ToString("#");
回答by Bilal
Total = Math.Ceiling(value)
Reply if it helps you
如果对你有帮助就回复
回答by Adedamola
string text = "19500.55";
text =(decimal.TryParse(text, out value))? (Math.Round(decimal.Parse(text))).ToString():"Invalid input";
