Python 从 tkinter 的网格中删除小部件
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remove widgets from grid in tkinter
提问by rodrigocf
I have a grid in a tkinter frame which displays query results. It has a date field that is changed manually and then date is used as a parameter on the query for those results. every time the date is changed, obviously the results change, giving a different amount of rows. The problem is that if you get less rows the second time you do it, you will still have results from the first query underneath those and will be very confusing.
我在 tkinter 框架中有一个网格，用于显示查询结果。它有一个手动更改的日期字段，然后将日期用作查询这些结果的参数。每次更改日期时，显然结果都会发生变化，给出不同数量的行。问题是，如果您第二次得到的行数较少，您仍然会在第一个查询下获得结果，并且会非常混乱。
My question is, how can i remove all rows from the frame that have a row number greater than 6 (regardless of what's in it)?
我的问题是，如何从框架中删除所有行号大于 6 的行（不管里面有什么）？
By the way, I'm running Python 3.3.3. Thanks in advance!
顺便说一下，我正在运行 Python 3.3.3。提前致谢！
采纳答案by jsbueno
Calling the method grid_forgeton the widget will remove it from the window -
this example uses the call grid_slaveson the parent to findout all
widgets mapped to the grid, and then the grid_infocall to learn about
each widget's position:
调用grid_forget小部件上的方法会将其从窗口中删除 - 此示例使用grid_slaves对父级的调用来查找映射到网格的所有小部件，然后grid_info调用以了解每个小部件的位置：
>>> import tkinter
# create:
>>> a = tkinter.Tk()
>>> for i in range(10):
... label = tkinter.Label(a, text=str(i))
... label.grid(column=0, row=i)
# remove from screen:
>>> for label in a.grid_slaves():
... if int(label.grid_info()["row"]) > 6:
... label.grid_forget()
