在 Python 中解析数字
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Parsing numbers in Python
提问by Hick
i want to take inputs like this 10 12
我想接受这样的输入 10 12
13 14
13 14
15 16
15 16
..
..
how to take this input , as two diffrent integers so that i can multiply them in python after every 10 and 12 there is newline
如何将此输入作为两个不同的整数，以便我可以在每 10 和 12 之后在 python 中将它们相乘有换行符
回答by Andrea Ambu
I'm not sure I understood your problem very well, it seems you want to parse two int separated from a space.
我不确定我是否很好地理解了您的问题，您似乎想解析两个与空格分开的 int。
In python you do:
在 python 中，你可以：
s = raw_input('Insert 2 integers separated by a space: ')
a,b = [int(i) for i in s.split(' ')]
print a*b
Explanation:
解释：
s = raw_input('Insert 2 integers separated by a space: ')
raw_input takes everything you type (until you press enter) and returns it as a string, so:
raw_input 接受您输入的所有内容（直到您按 Enter 键）并将其作为字符串返回，因此：
>>> raw_input('Insert 2 integers separated by a space: ')
Insert 2 integers separated by a space: 10 12
'10 12'
In s you have now '10 12', the two int are separated by a space, we split the string at the space with
在 s 中你现在有 '10 12'，两个 int 被一个空格隔开，我们在空格处分割字符串
>>> s.split(' ')
['10', '12']
now you have a list of strings, you want to convert them in int, so:
现在您有一个字符串列表，您想将它们转换为 int，因此：
>>> [int(i) for i in s.split(' ')]
[10, 12]
then you assign each member of the list to a variable (a and b) and then you do the product a*b
然后将列表的每个成员分配给一个变量（a 和 b），然后执行乘积 a*b
回答by Nicolas Dumazet
f = open('inputfile.txt')
for line in f.readlines():
# the next line is equivalent to:
# s1, s2 = line.split(' ')
# a = int(s1)
# b = int(s2)
a, b = map(int, line.split(' '))
print a*b
回答by Dario
You could use regular expressions (re-module)
您可以使用正则表达式（re-module）
import re
test = "10 11\n12 13" # Get this input from the files or the console
matches = re.findall(r"(\d+)\s*(\d+)", test)
products = [ int(a) * int(b) for a, b in matches ]
# Process data
print(products)
