scala 如何在scala中读取属性文件
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how to read properties file in scala
提问by sunil
I am new to Scala programming and I wanted to read a properties file in Scala.
我是 Scala 编程的新手，我想在 Scala 中读取属性文件。
I can't find any APIs to read a property file in Scala.
我找不到任何 API 来读取 Scala 中的属性文件。
Please let me know if there are any API for this or other way to read properties files in Scala.
请让我知道是否有任何 API 可以通过这种方式或其他方式读取 Scala 中的属性文件。
回答by 4lex1v
回答by Jatin
You will have to do it in similar way you would with with Scala Mapto java.util.Map. java.util.Propertiesextends java.util.HashTablewhiche extends java.util.Dictionary.
您必须以与使用 Scala Mapto java.util.Map. java.util.Properties延伸java.util.HashTablewhiche 延伸java.util.Dictionary。
scala.collection.JavaConvertershas functions to convert to and fro from Dictionaryto Scala mutable.Map:
scala.collection.JavaConverters具有Dictionary在 Scala和Scala 之间来回转换的函数mutable.Map：
val x = new Properties
//load from .properties file here.
import scala.collection.JavaConverters._
scala> x.asScala
res4: scala.collection.mutable.Map[String,String] = Map()
You can then use Mapabove. To get and retrieve. But if you wish to convert it back to Propertiestype (to store back etc), you might have to type cast it manually then.
然后就可以使用Map上面的了。获取和检索。但是，如果您希望将其转换回Properties类型（以存储回等），那么您可能必须手动进行类型转换。
回答by Raul
Consider something along the lines
考虑一些事情
def getPropertyX: Option[String] = Source.fromFile(fileName)
.getLines()
.find(_.startsWith("propertyX="))
.map(_.replace("propertyX=", ""))
