PHP：字符串中的变量没有连接
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PHP: variables in strings without concatenation
提问by lemon
If I have a variable $var in this string:
echo "Hello, there are many $vars";
如果我在这个字符串中有一个变量 $var：
echo "Hello, there are many $vars";
Php looks for the variable $varsinstead of $var.
Php 寻找variable $vars代替$var。
Without concatenation like: "Hello, there are many $var" . "s";
is there another way to do this, like some sort of escaping character?
没有像这样的连接："Hello, there are many $var" . "s";
有没有另一种方法可以做到这一点，比如某种转义字符？
回答by Tristan
回答by Madara's Ghost
You can use {}to escape your variable properly. Consider the following example:
您可以使用{}来正确转义您的变量。考虑以下示例：
echo "There are many ${var}s"; #Or...
echo "There are many {$var}s";
回答by Pelshoff
Alternatively you may want to look at sprintf: http://php.net/manual/en/function.sprintf.php
或者，您可能想查看 sprintf：http: //php.net/manual/en/function.sprintf.php
The sprintf function allows you to format any type of variable as a string in a specific notation.
sprintf 函数允许您将任何类型的变量格式化为特定符号中的字符串。
回答by Kokos
Personally I always divide the variables from a string like this: echo 'Hello, there are many '.$var.'s';
我个人总是从这样的字符串中划分变量： echo 'Hello, there are many '.$var.'s';
Mostly because of readability, if you go through your code it's instantly clear where the variables are.
主要是因为可读性，如果你仔细阅读你的代码，它会立即清楚变量在哪里。
