C++ 将两个点转换为矩形 (cv::Rect)
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Convert two points to a rectangle (cv::Rect)
提问by Karthik_elan
I have two points (assumed to be from rectangle, which are its top-left corner & bottom-right corner).
我有两点（假设来自矩形，即它的左上角和右下角）。
Point pTopLeft;
Point pBottomRight;
I want to formulate a cv::Rect using these points. So, I tried
我想用这些点来制定一个 cv::Rect 。所以，我试过了
cv::Rect rRect;
rRect.tl() = pTopLeft;
rRect.br() = pBottomRight;
There is no error. But the Rectseems to be containing nothing. i.e., both the points are indicating zero. So, How do I formulate a new Rect object with arbitrary two points ?
没有错误。但是Rect似乎什么都不包含。即，两个点都指示为零。那么，如何用任意两点来制定一个新的 Rect 对象？
回答by berak
since Rect::tl() and Rect::br() just return copies, not references, try a constructor:
由于 Rect::tl() 和 Rect::br() 只返回副本，而不是引用，请尝试构造函数：
cv::Rect rRect(pTopLeft, pBottomRight);
回答by Grégory NEUT
You have to calcul basic informations from your two points. Width and height, and then create new object using the following constructor :
你必须从你的两点来计算基本信息。宽度和高度，然后使用以下构造函数创建新对象：
(Object) rect(x, y, width, height)
pTopLeft.x = x
pTopLeft.y = y
pBottomRight.x - pTopLeft.x = width
pTopLeft.y - pBottomRight.y = height
回答by Haris
You can make it this way also,
你也可以这样做，
Point pTopLeft;
Point pBottomRight;
cv::Rect rRect(pTopLeft.x,pTopLeft.y,pBottomRight.x-pTopLeft.x,pBottomRight.y-pTopLeft.y);
