Python Matplotlib：指定刻度标签的浮点数格式

Matplotlib: Specify format of floats for tick labels

提问by albert

I am trying to set the format to two decimal numbers in a matplotlib subplot environment. Unfortunately, I do not have any idea how to solve this task.

我试图在 matplotlib 子图环境中将格式设置为两个十进制数。不幸的是，我不知道如何解决这个任务。

To prevent using scientific notation on the y-axis I used ScalarFormatter(useOffset=False)as you can see in my snippet below. I think my task should be solved by passing further options/arguments to the used formatter. However, I could not find any hint in matplotlib's documentation.

为了防止在 y 轴上使用科学记数法，我使用了ScalarFormatter(useOffset=False)以下代码片段。我认为我的任务应该通过将更多选项/参数传递给使用的格式化程序来解决。但是，我在 matplotlib 的文档中找不到任何提示。

How can I set two decimal digits or none (both cases are needed)? I am not able to provide sample data, unfortunately.

如何设置两位十进制数字或无（两种情况都需要）？不幸的是，我无法提供示例数据。

---

---

-- SNIPPET --

-- 片段 --

f, axarr = plt.subplots(3, sharex=True)

data = conv_air
x = range(0, len(data))

axarr[0].scatter(x, data)
axarr[0].set_ylabel('$T_\mathrm{air,2,2}$', size=FONT_SIZE)
axarr[0].yaxis.set_major_locator(MaxNLocator(5))
axarr[0].yaxis.set_major_formatter(ScalarFormatter(useOffset=False))
axarr[0].tick_params(direction='out', labelsize=FONT_SIZE)
axarr[0].grid(which='major', alpha=0.5)
axarr[0].grid(which='minor', alpha=0.2)

data = conv_dryer
x = range(0, len(data))

axarr[1].scatter(x, data)
axarr[1].set_ylabel('$T_\mathrm{dryer,2,2}$', size=FONT_SIZE)
axarr[1].yaxis.set_major_locator(MaxNLocator(5))
axarr[1].yaxis.set_major_formatter(ScalarFormatter(useOffset=False))
axarr[1].tick_params(direction='out', labelsize=FONT_SIZE)
axarr[1].grid(which='major', alpha=0.5)
axarr[1].grid(which='minor', alpha=0.2)

data = conv_lambda
x = range(0, len(data))

axarr[2].scatter(x, data)
axarr[2].set_xlabel('Iterationsschritte', size=FONT_SIZE)
axarr[2].xaxis.set_major_locator(MaxNLocator(integer=True))
axarr[2].set_ylabel('$\lambda$', size=FONT_SIZE)
axarr[2].yaxis.set_major_formatter(ScalarFormatter(useOffset=False))
axarr[2].yaxis.set_major_locator(MaxNLocator(5))
axarr[2].tick_params(direction='out', labelsize=FONT_SIZE)
axarr[2].grid(which='major', alpha=0.5)
axarr[2].grid(which='minor', alpha=0.2)

采纳答案by tacaswell

See the relevant documentation in generaland specifically

请参阅一般和具体的相关文档

from matplotlib.ticker import FormatStrFormatter

fig, ax = plt.subplots()

ax.yaxis.set_major_formatter(FormatStrFormatter('%.2f'))

回答by sapo_cosmico

The answer above is probably the correct way to do it, but didn't work for me.

上面的答案可能是正确的方法，但对我不起作用。

The hacky way that solved it for me was the following:

为我解决它的hacky方法如下：

ax = <whatever your plot is> 
# get the current labels 
labels = [item.get_text() for item in ax.get_xticklabels()]
# Beat them into submission and set them back again
ax.set_xticklabels([str(round(float(label), 2)) for label in labels])
# Show the plot, and go home to family 
plt.show()

回答by CodeWarrior

If you are directly working with matplotlib's pyplot (plt) and if you are more familiar with the new-style format string, you can try this:

如果你直接使用 matplotlib 的 pyplot (plt) 并且你对新式格式字符串比较熟悉，你可以试试这个：

from matplotlib.ticker import StrMethodFormatter
plt.gca().yaxis.set_major_formatter(StrMethodFormatter('{x:,.0f}')) # No decimal places
plt.gca().yaxis.set_major_formatter(StrMethodFormatter('{x:,.2f}')) # 2 decimal places

From the documentation:

从文档：

class matplotlib.ticker.StrMethodFormatter(fmt)

Use a new-style format string (as used by str.format()) to format the tick.

The field used for the value must be labeled x and the field used for the position must be labeled pos.

类 matplotlib.ticker.StrMethodFormatter(fmt)

使用新样式的格式字符串（如 str.format() 使用的那样）来格式化刻度线。

用于值的字段必须标记为 x，用于位置的字段必须标记为 pos。

回答by foxpal

In matplotlib 3.1, you can also use ticklabel_format. To prevents scientific notation without offsets:

在 matplotlib 3.1 中，您还可以使用ticklabel_format。防止没有偏移的科学记数法：

plt.gca().ticklabel_format(axis='both', style='plain', useOffset=False)