如何在python中检查字符串中的精确单词
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How do I check for an EXACT word in a string in python
提问by user2750103
Basically I need to find a way to figure out a way to find the EXACT word in a string. All the information i have read online has only given me how to search for letters in a string so
基本上我需要找到一种方法来找出在字符串中找到精确单词的方法。我在网上阅读的所有信息只告诉了我如何在字符串中搜索字母，所以
98787This is correct
98787这是正确的
will still come back as true in an if statement.
仍然会在 if 语句中返回为真。
This is what I have so far.
这是我到目前为止。
elif 'This is correct' in text:
print("correct")
This will work with any combination of letters before the Correct... For example fkrjCorrect, 4123Correct and lolcorrect will all come back as true in the if statement. When I want it to come back as true only IF it exactly matches "This is correct"
这将适用于正确之前的任何字母组合...例如，fkrjCorrect、4123Correct 和 lolcorrect 在 if 语句中都将返回为真。当我希望它仅在它与“这是正确的”完全匹配时才返回真实
回答by TerryA
Use the comparison operator ==instead of inthen:
使用比较运算符==而不是inthen：
if text == 'This is correct':
print("Correct")
This will check to see if the whole string is just 'This is correct'. If it isn't, it will be False
这将检查整个字符串是否只是'This is correct'. 如果不是，它将是False
回答by Birei
You can use the word-boundaries of regular expressions. Example:
您可以使用正则表达式的词边界。例子：
import re
s = '98787This is correct'
for words in ['This is correct', 'This', 'is', 'correct']:
if re.search(r'\b' + words + r'\b', s):
print('{0} found'.format(words))
That yields:
这产生：
is found
correct found
EDIT: For an exact match, replace \bassertions with ^and $to restrict the match to the begin and end of line.
EDIT：对于完全匹配，替换\b使用断言^和$所述开始和线路的端部以限制匹配。
回答by Bor
You can make a few changes.
您可以进行一些更改。
elif 'This is correct' in text[:len('This is correct')]:
or
或者
elif ' This is correct ' in ' '+text+' ':
Both work. The latter is more flexible.
两者都有效。后者更灵活。
回答by Simon Callan
I suspect that you are looking for the startswith()function. This checks to see if the characters in a string match at the start of another string
我怀疑您正在寻找该startswith()功能。这会检查字符串中的字符是否与另一个字符串的开头匹配
"abcde".startswith("abc") -> true
"abcde".startswith("bcd") -> false
There is also the endswith()function, for checking at the other end.
还有一个endswith()功能，用于检查另一端。
回答by sharcashmo
Actually, you should look for 'This is correct' string surrounded by word boundaries.
实际上，您应该寻找被单词边界包围的“这是正确的”字符串。
So
所以
import re
if re.search(r'\bThis is correct\b', text):
print('correct')
should work for you.
应该为你工作。
回答by Toshiro
Break up the string into a list of strings with .split() then use the in operator.
使用 .split() 将字符串分解为字符串列表，然后使用 in 运算符。
This is much simpler than using regular expressions.
这比使用正则表达式简单得多。
回答by Jash Enakulapati
Below is a solution without using regular expressions. The program searches for exact word in this case 'CASINO' and prints the sentence.
以下是不使用正则表达式的解决方案。程序在本例中搜索确切的单词“CASINO”并打印句子。
words_list = [ "The Learn Python Challenge Casino.", "They bought a car while at
the casino", "Casinoville" ]
search_string = 'CASINO'
def text_manipulation(words_list, search_string):
search_result = []
for sentence in words_list:
words = sentence.replace('.', '').replace(',', '').split(' ')
[search_result.append(sentence) for w in words if w.upper() ==
search_string]
print(search_result)
text_manipulation(words_list, search_string)
This will print the results - ['The Learn Python Challenge Casino.', 'They bought a car while at the casino']
这将打印结果 - ['The Learn Python Challenge Casino.', '他们在赌场买了一辆车']
