typescript 如何使用静态方法声明接口？
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How to declare an interface with static method?
提问by Gill Bates
I want to declare an alternative constructor in interface - bazin IFoo, but seems like it's impossible in TypeScript:
我想在 interface - bazin 中声明一个替代构造函数IFoo，但在 TypeScript 中似乎是不可能的：
interface IFoo {
bar(): boolean;
static baz(value): IFoo;
}
class Foo implements IFoo {
constructor(private qux) {}
bar(): boolean {
return this.qux;
}
static baz(value): IFoo {
return new Foo(value);
}
}
What is the way to do that and have a proper type checking for baz?
有什么方法可以做到这一点并进行适当的类型检查baz？
回答by chris
you can do this with anonymous classes:
你可以用匿名类来做到这一点：
In general
一般来说
export const MyClass: StaticInterface = class implements InstanceInterface {
}
Your example:
你的例子：
interface IFooStatic {
baz(value): IFoo;
}
interface IFoo {
bar(): boolean;
}
const Foo: IFooStatic = class implements IFoo {
constructor(private qux) {}
bar(): boolean {
return this.qux;
}
static baz(value): IFoo {
return new Foo(value);
}
}
回答by Martin Vseticka
Interfaces do not supportstatic methods.
接口不支持静态方法。
You can't use abstract classesfor your problem too:
interface IFoo {
bar(): boolean;
}
abstract class FooBase {
abstract static baz(value): IFoo; // this is NOT allowed
}
class Foo extends FooBase {
constructor(private qux) {
super();
}
bar(): boolean {
return this.qux;
}
static baz(value): IFoo {
return new Foo(value);
}
}
回答by FlorianTopf
You can't define a static in an interface in TypeScript. If you want to have type checking for the factory method just remove statickeyword.
您不能在 TypeScript 的接口中定义静态。如果您想对工厂方法进行类型检查，只需删除static关键字。
You can still use the factory method like this over the prototypeproperty:
您仍然可以在prototype属性上使用这样的工厂方法：
var FootInstance = Foo.prototype.baz('test');
var FootInstance = Foo.prototype.baz('test');
