Javascript js打开弹出窗口并在另一个页面中访问其元素
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js open popup window and acces its element in another page
提问by Suneth Kalhara
I have a problem with js popup window.
我有 js 弹出窗口的问题。
I open a popup and try to access its elements in another page page, no success, and I don't want to reload the popup source, I simply want access a element of the opened popup
我打开一个弹出窗口并尝试访问另一个页面页面中的元素，没有成功，我不想重新加载弹出源，我只想访问打开的弹出窗口的元素
Ex -
前任 -
- 1st page - opened popup with html5 music player
- 2nd page - need to pause the music when user click on button on main page
- 第一页 - 使用 html5 音乐播放器打开弹出窗口
- 第二页 - 当用户点击主页上的按钮时需要暂停音乐
1st page
第一页
var popup = window.open("test.html","mypopup","width=500,height=300");
2nd page I want to access mypopup windows elements without reloading the popup
第二页我想在不重新加载弹出窗口的情况下访问 mypopup 窗口元素
I only need the way how to access opened popup elements without interrupting its sources using JS or JQuery
我只需要如何访问打开的弹出元素而不使用 JS 或 JQuery 中断其源的方法
回答by mplungjan
Same origin (domain, port and protocol)?
同源（域、端口和协议）？
Plain JS:
普通JS：
from page1
从第 1 页
var popup = window.open("test.html","mypopup","width=500,height=300");
popup.document.getElementById("player").someFunction();
from page 2
从第 2 页
var popup = window.open('','mypopup');
// now popup is known again
popup.document.getElementById("player").someFunction();
