php SyntaxError: JSON.parse: JSON 数据第 1 行第 2 列的意外字符 -- FireBug 报告此错误。有什么解决办法吗？
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SyntaxError: JSON.parse: unexpected character at line 1 column 2 of the JSON data -- FireBug reports this error. Any solution?
提问by Faizuddin Mohammed
I have used Laravel Response::json to generate a JSON response.
我使用 Laravel Response::json 来生成 JSON 响应。
return Response::json(array('subjects' => $subjects, 'year' => $year, 'sem' => $sem));
When I run the request, I get a valid JSON (tested in JSONLint) as a response.
当我运行请求时，我得到一个有效的 JSON（在 JSONLint 中测试）作为响应。
But the following jQuery method fails: $.parseJSON(data)
但以下 jQuery 方法失败： $.parseJSON(data)
I get the following error in FireBug:
我在 FireBug 中收到以下错误：
SyntaxError: JSON.parse: unexpected character at line 1 column 2 of the JSON data
SyntaxError: JSON.parse: JSON 数据第 1 行第 2 列的意外字符
The Response I recieve:
我收到的回复：
{
"subjects": [
{
"id": 1,
"name": "Control Systems",
"semester": 1,
"year": 3,
"branch_id": 4
},
{
"id": 2,
"name": "Analog Communications",
"semester": 1,
"year": 3,
"branch_id": 4
},
{
"id": 3,
"name": "Linear IC Applications",
"semester": 1,
"year": 3,
"branch_id": 4
},
{
"id": 4,
"name": "Antennas & Wave Propagation",
"semester": 1,
"year": 3,
"branch_id": 4
}
],
"year": 3,
"sem": 2
}
And the code where I'm trying to parse it:
以及我试图解析它的代码：
$(document).ready(function() {
$('#branchAndSubjects').click(function() {
$.post('/findBranchAndSubjects', {
roll: roll,
_token: "{{csrf_token()}}"
}, function(data) {
var subjects = $.parseJSON(data);
});
});
});
回答by T.J. Crowder
If you're doing the Since you're doing the $.parseJSON(data)in an ajax success handler$.parseJSON(data)in an ajax success handler, the problem is almost certainly that jQuery has alreadyparsed it for you. jQuery will look at the Content-Typeof the response and, if it's application/json, it will parse it, and provide the parsed result to your success handler. The first thing that will happen if you pass that into $.parseJSONwill be that it will get converted back to a string ("[object Object]", in your case), which $.parseJSONwill then fail to parse.
如果您既然您$.parseJSON(data)在 ajax 成功处理程序中执行$.parseJSON(data)在 ajax 成功处理程序中执行了 ，那么问题几乎肯定是 jQuery已经为您解析了它。jQuery 将查看Content-Type响应的 ，如果是application/json，它将解析它，并将解析的结果提供给您的成功处理程序。如果您$.parseJSON将其传递给它，首先会发生的事情是它将被转换回字符串（"[object Object]"在您的情况下为 ），然后$.parseJSON将无法解析。
Just use dataas-is, it's already an object, thanks to the automatic parsing:
只需data按原样使用，由于自动解析，它已经是一个对象：
$(document).ready(function() {
$('#branchAndSubjects').click(function() {
$.post('/findBranchAndSubjects', {
roll: roll,
_token: "{{csrf_token()}}"
}, function(data) {
console.log(data.year); // 3
console.log(data.subjects.length); // 4
console.log(data.subjects[0].name); // Control Systems
});
});
});
