Laravel 4 如何使用路由名称别名（使用）与 Route::controller
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Laravel 4 how to use the route name alias (uses) with Route::controller
提问by James
Rather than using Route::get, Route::postetc for my controller requests I decided to use the Route::controllermethod, really helps cut down on code lines in route.php.
而不是使用Route::get，Route::post等我控制器请求我决定使用Route::controller方法，确实有助于减少在代码行route.php。
However I had previously set up some "route" names, for example my previous code included:
但是我之前已经设置了一些“路线”名称，例如我之前的代码包括：
Route::get('admin/baserate/view', array('as' => 'baserateview','uses'=>'BaserateController@getView'));
but now I'm using Route::controllerI don't know how to implement the route alias name "baserateview". My new code looks like:
但现在我正在使用Route::controller我不知道如何实现路由别名“baserateview”。我的新代码如下所示：
Route::controller('admin/baserate', 'BaserateController');
Is there any way I can do this?
有什么办法可以做到这一点吗？
回答by Andrew Halls
You can do this in the following way:
您可以通过以下方式执行此操作：
// User Controller
Route::controller(
'users',
'AdminUserController',
array(
'getView' => 'admin.users.view',
'getEdit' => 'admin.users.edit',
'getList' => 'admin.users.list',
'getAdd' => 'admin.users.add',
'getUndelete' => 'admin.users.undelete',
'postDelete' => 'admin.users.delete'
)
);
回答by James
Ok so it isn't possible to do it all on the Route:controller line. I'd have to go with both lines:
好的，所以不可能在 Route:controller 线上完成所有操作。我必须同时使用两条线：
Route::controller('admin/baserate', 'BaserateController');
Route::get('admin/baserate/view', array('as' => 'baserateview','uses'=>'BaserateController@getView'));
...which works fine. I was just hoping that there would be a way to specify that one of the methods inside the controller has a named route without having to use two lines
...这工作正常。我只是希望有一种方法可以指定控制器内的一个方法具有命名路由，而不必使用两行
Thanks anyway
不管怎么说，还是要谢谢你
