javascript 无法让谷歌地图computeDistanceBetween()返回一个值
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Can't get google maps computeDistanceBetween() to return a value
提问by slapee
The computeDistanceBetween()function in google maps geometry library will not return a value for me. Using the alertfunction it says the distance is "[object, Object]". Can anyone see where I'm going wrong? here are the important parts of the code in question:
computeDistanceBetween()谷歌地图几何库中的函数不会为我返回值。使用该alert函数，它表示距离是“[object, Object]”。谁能看到我哪里出错了？以下是相关代码的重要部分：
<script type="text/javascript" src="http://maps.googleapis.com/maps/api/js?sensor=false&libraries=geometry"></script>
<script type="text/javascript" >
var myArray1= [['location1', lat1, lng1], ['location2', lat2, lng2], ...];
var myArray2= [['locationA', latA, lngA], ['locationB', latB, lngB], ...];
var arrays = [myArray1, myArray2];
function codeStart() {
var orig;
var startAddress = document.getElementById("start").value;
geocoder.geocode( { 'address': startAddress}, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
var i = 0;
var input = results[0].geometry.location;
while (i < arrays.length) {
orig = closest(input, arrays[i]);
}
}
});
}
function closest(latlng, array){
var distance;
var c = 0;
while (c < array.length){
var location = array[c];
var locationlatlng = new google.maps.LatLng(location[1],location[2]);
distance = new google.maps.geometry.spherical.computeDistanceBetween(latlng, locationlatlng);
alert(distance); // popup box says "[object, Object]"
c++;
}
}
</script>
回答by Trott
computeDistanceBetweenis a static method. So this line:
computeDistanceBetween是一个静态方法。所以这一行：
distance = new google.maps.geometry.spherical.computeDistanceBetween(latlng, locationlatlng);
should be this instead:
应该是这样的：
distance = google.maps.geometry.spherical.computeDistanceBetween(latlng, locationlatlng)
By the way, when alert()tells you that something is an object, it's a good time to switch to console.dir()instead of alert()so you can (at least in some browsers) look at the contents of the object in the console/dev tools. If you don't know much about your JavaScript console, check it out. It will save you tons of time.
顺便alert()说一句，当告诉您某物是一个对象时，现在是切换到console.dir()而不是alert()这样的好时机，这样您就可以（至少在某些浏览器中）在控制台/开发工具中查看对象的内容。如果您不太了解 JavaScript 控制台，请查看它。它将为您节省大量时间。
回答by Lightness Races in Orbit
distance = new google.maps.geometry.spherical.computeDistanceBetween(latlng, locationlatlng);
For some reason you've used the syntax to create a new object. That is why, when you alert(distance), you're seeing that distanceis an object.
出于某种原因，您使用语法创建了一个新对象。这就是为什么，当你alert(distance)，你看到那distance是一个对象。
computeDistanceBetweenis just a function:
distance = google.maps.geometry.spherical.computeDistanceBetween(latlng, locationlatlng);
