ios 带有 URL 内容的字符串？
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String With Contents Of URL?
提问by imnilly
So before I downloaded the recent update, the following code worked for me:
所以在我下载最近的更新之前，以下代码对我有用：
var g_home_url = String.stringWithContentsOfURL(NSURL(string: url_string), encoding: NSUTF8StringEncoding, error: nil) // Gives me an error: "String.Type does not have a member names stringWithContentsOfUrl"
I am confused. What is the proper way to acieve the following objective-c method in swift?
我很迷惑。在swift中实现以下objective-c方法的正确方法是什么？
NSString * g_home_url = [[NSString alloc] initWithContentsOfURL:[NSURL URLWithString:home_url] encoding:NSUTF8StringEncoding error:nil];
回答by Guillaume Algis
Use the -initWithContentsOfURL:encoding:error:instance method instead of the +stringWithContentsOfURL:encoding:error:class convenience initializer.
使用-initWithContentsOfURL:encoding:error:实例方法而不是+stringWithContentsOfURL:encoding:error:类便利初始值设定项。
var g_home_url = String(contentsOfURL: NSURL(string: url_string)!, encoding: NSUTF8StringEncoding, error: nil)
I have no idea if class convenience initializers are now unsupported in Swift, but it would make sense as they were just shorthands for the alloc-init boilerplate, which doesn't exist in Swift.
我不知道 Swift 现在是否不支持类便利初始化程序，但这是有道理的，因为它们只是 alloc-init 样板的简写，而 Swift 中不存在。
回答by Niklas Berglund
For Swift 3 you'll have to use String(contentsOf:encoding:). It throws.
对于 Swift 3，您必须使用String(contentsOf:encoding:). 它抛出。
do {
var content = try String(contentsOf:URL(string: "http://your-URI-here")!)
}
catch let error {
// Error handling
}
回答by Sergey Di
At this moment (Swift 4.1.2) the only one way to send HTTP-get request from Ubuntu linux is: https://github.com/dmcyk/SwiftyCurl
目前（Swift 4.1.2）从 Ubuntu linux 发送 HTTP-get 请求的唯一方法是：https: //github.com/dmcyk/SwiftyCurl
import Foundation
import SwiftyCurl
var request = cURLRequest(url: URL(string: "https://path.to/url/")!, method: .get)
let connection = cURLConnection(useSSL: true)
do {
let res = try connection.request(request)
if let body: String = res.body() {
print(body)
}
} catch {
prin(error)
}
回答by Sasi M
For Swift 4 they have changed string encoding. So now it will be,
对于 Swift 4，他们更改了字符串编码。所以现在将是，
do {
var g_home_url = try String(contentsOfURL: URL.init(string: url_string)!, encoding: String.Encoding.utf8)
}
catch {
print(error)
}
回答by Manu
Here what it worked for me: (There is no more error argument)
这对我有用：（没有更多的错误参数）
var g_home_url = try! String(contentsOfURL: NSURL(string: url_string)!, encoding: NSUTF8StringEncoding)
or if you want to handle the error:
或者如果你想处理错误：
do {
var g_home_url = try String(contentsOfURL: NSURL(string: url_string)!, encoding: NSUTF8StringEncoding)
}
catch {
print(error)
}
