从 bash 脚本发送 POST 请求
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Sending POST Request from bash script
提问by Bercovici Adrian
I want to execute a bashscript after i make a POSTrequest.So far i am using Postmanfor sending the request , but i was wondering if i can somehow do it from a bashscript as well with a jsonfile as parameter.
我想bash在发出POST请求后执行一个脚本。到目前为止，我正在使用它Postman来发送请求，但我想知道我是否可以从bash脚本以及将json文件作为参数以某种方式执行此操作。
I have looked into curlso far but it does not work:
curl到目前为止，我已经研究过，但它不起作用：
bash file
bash文件
curl -X POST -d req.json http://localhost:9500
Json file (req.json)
JSON 文件 ( req.json)
{
"id":5,
"name":"Dan",
"age":33,
"cnp":33,
"children":100,
"isMarried":0
}
I just get the error :
我只是收到错误：
HTTP/1.0 503 Service Unavailable
with the trailing HTML
与尾随 HTML
采纳答案by edaemon
curlshould do the job. This will send a normal POST request using the data in req.jsonas the body:
curl应该做的工作。这将使用数据req.json作为正文发送一个普通的 POST 请求：
curl -X POST -H "Content-Type: application/json" -d @req.json http://localhost:9500
The elements you were missing are -H "Content-Type: application/json"and the @in the data flag. Without the -Hflag as above curlwill send a content type of application/x-www-form-urlencoded, which most applications won't accept if they expect JSON. The @in the -dflag informs curlthat you are passing a file name; otherwise it uses the text itself (i.e. "req.json") as the data.
您缺少的元素是-H "Content-Type: application/json"和@数据标志中的 。如果没有上述-H标志，curl将发送内容类型application/x-www-form-urlencoded，如果他们期望 JSON，大多数应用程序将不会接受。将@在-d标志运筹学curl要传递一个文件名; 否则它使用文本本身（即“req.json”）作为数据。
