bash sed/awk - 如何删除少于 3 列的行
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sed/awk - How to remove lines with less than 3 columns
提问by Numpty
Really simple question. I simply need to remove lines from a list when there are less than 3 columns
真的很简单的问题。当少于 3 列时，我只需要从列表中删除行
Eg:
例如：
a b c
a b <--- This one needs to disappear
a b c
I'm pretty sure awk NF does it, however I can't seem to get it right.
我很确定 awk NF 会这样做，但是我似乎无法正确完成。
Thanks in advance!
提前致谢！
回答by Kent
sed, grep, awk all can do this job. since you prefer awk, see if this helps?
sed、grep、awk 都可以完成这项工作。因为你更喜欢 awk，看看这是否有帮助？
awk 'NF>=3' file
