bash 当“find”返回多个结果时，为什么会触发错误“find:path must precede expression”
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Why does the error "find: paths must precede expression" trigger when multiple results are returned from "find"
提问by Dave
Why does the error find: paths must precede expression: input.txt trigger when multiple results are returned from "find" in subprocess but not when a single result is returned?
当子进程中的“find”返回多个结果而不是返回单个结果时，为什么会出现错误 find:paths must preceto expression: input.txt 触发？
The dir contains three files.
该目录包含三个文件。
ls
input2.txt input.txt input.log
There is only one file matching the find query and the result can be assigned to $foo
只有一个文件匹配查找查询，结果可以分配给 $foo
$ foo=$(find . -name *.log )
echo $foo
./plot.log
When > 1reults are returned find throw's an error.
当 > 1返回结果时，发现抛出错误。
$ foo=$(find . -name *.txt )
find: paths must precede expression: input.txt
I don't understand why this is happening.
我不明白为什么会这样。
回答by l0b0
You need to quotespecial characters, because globs are expandedbefore running the command:
find . -name '*.txt'
To see how globbing works, try for example echo *.txt- it will onlyactually print *.txtif there are no files in the current directory ending with .txt.
要了解通配符的作品，尝试例如echo *.txt-这将仅实际打印*.txt，如果有在当前目录中没有文件结尾.txt。
