Xcode Webview 打开 URL
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/10938660/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Xcode Webview Open Url
提问by Kevin G
I'm trying to develop a web browser that will display a website after the launch . I already red the articles and with i cant seem to get it to work with this code .
我正在尝试开发一个将在启动后显示网站的网络浏览器。我已经把文章写红了，但我似乎无法让它与这段代码一起工作。
NSURL*url=[NSURL URLWithString:@"http://www.google.com"];
NSURLRequest*request=[NSURLRequest requestWithURL:url];
[[webview mainFrame] loadRequest:request];
I'm using the cocoa and the Webkit Framework .
我正在使用可可和 Webkit 框架。
回答by jediob1
Try this:
尝试这个：
- (void)applicationDidFinishLaunching:(NSNotification *)notification{
NSString *urlText = @"http://google.com";
[[myWebView mainFrame] loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:urlText]]];
return;
}
if that doesn't work, try this:
如果这不起作用，请尝试以下操作：
- (void)awakeFromNib{
NSString *urlText = @"http://google.com";
[[myWebView mainFrame] loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:urlText]]];
return;
}
Good luck! tell me if this works!
祝你好运！告诉我这是否有效！
回答by rishi
Use -
用 -
[webview loadRequest:request];
