C++ term 不计算为采用 1 个参数的函数
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term does not evaluate to a function taking 1 arguments
提问by pingu
Can someone explain why I am getting:
有人可以解释为什么我得到：
error C2064: term does not evaluate to a function taking 1 arguments
错误 C2064：术语不计算为采用 1 个参数的函数
for the line:
对于该行：
DoSomething->*pt2Func("test");
with this class
与这堂课
#ifndef DoSomething_H
#define DoSomething_H
#include <string>
class DoSomething
{
public:
DoSomething(const std::string &path);
virtual ~DoSomething();
void DoSomething::bar(const std::string &bar) { bar_ = bar; }
private:
std::string bar_;
};
#endif DoSomething_H
and
和
#include "DoSomething.hpp"
namespace
{
void foo(void (DoSomething::*pt2Func)(const std::string&), doSomething *DoSomething)
{
doSomething->*pt2Func("test");
}
}
DoSomething::DoSomething(const std::string &path)
{
foo(&DoSomething::bar, this);
}
回答by Andy Prowl
Problem #1:The name of the second argument and the type of the second argument are swapped somehow. It should be:
问题 #1：第二个参数的名称和第二个参数的类型以某种方式交换。它应该是：
DoSomething* doSomething
// ^^^^^^^^^^^ ^^^^^^^^^^^
// Type name Argument name
Instead of:
代替：
doSomething* DoSomething
Which is what you have.
这就是你所拥有的。
Problem #2:You need to add a couple of parentheses to get the function correctly dereferenced:
问题#2：您需要添加几个括号才能正确取消引用该函数：
(doSomething->*pt2Func)("test");
// ^^^^^^^^^^^^^^^^^^^^^^^
Eventually, this is what you get:
最终，这就是你得到的：
void foo(
void (DoSomething::*pt2Func)(const std::string&),
DoSomething* doSomething
)
{
(doSomething->*pt2Func)("test");
}
And here is a live exampleof your program compiling.
这是你的程序编译的一个活生生的例子。
