如何使用 JavaScript 或 jQuery 更改数组内对象的值?
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How to change value of object which is inside an array using JavaScript or jQuery?
提问by qinHaiXiang
The code below comes from jQuery UI Autocomplete:
下面的代码来自 jQuery UI 自动完成:
var projects = [
{
value: "jquery",
label: "jQuery",
desc: "the write less, do more, JavaScript library",
icon: "jquery_32x32.png"
},
{
value: "jquery-ui",
label: "jQuery UI",
desc: "the official user interface library for jQuery",
icon: "jqueryui_32x32.png"
},
{
value: "sizzlejs",
label: "Sizzle JS",
desc: "a pure-JavaScript CSS selector engine",
icon: "sizzlejs_32x32.png"
}
];
For example, I want to change the desc value of jquery-ui. How can I do that?
例如,我想更改jquery-ui的desc 值。我怎样才能做到这一点?
Additionally, is there a faster way to get the data? I mean give the object a name to fetch its data, just like the object inside an array? So it would be something like jquery-ui.jquery-ui.desc = ....
另外,有没有更快的方法来获取数据?我的意思是给对象一个名字来获取它的数据,就像数组中的对象一样?所以它会是这样的jquery-ui.jquery-ui.desc = ....
采纳答案by Aston
You have to search in the array like:
您必须在数组中搜索,例如:
function changeDesc( value, desc ) {
for (var i in projects) {
if (projects[i].value == value) {
projects[i].desc = desc;
break; //Stop this loop, we found it!
}
}
}
and use it like
并像使用它一样
var projects = [ ... ];
changeDesc ( 'jquery-ui', 'new description' );
UPDATE:
更新:
To get it faster:
要更快地获得它:
var projects = {
jqueryUi : {
value: 'lol1',
desc: 'lol2'
}
};
projects.jqueryUi.desc = 'new string';
(In according to Frédéric's comment you shouldn't use hyphen in the object key, or you should use "jquery-ui" and projects["jquery-ui"] notation.)
(根据 Frédéric 的评论,您不应该在对象键中使用连字符,或者您应该使用“jquery-ui”和 projects[“jquery-ui”] 符号。)
回答by Umair Ahmed
It is quite simple
这很简单
- Find the index of the object using
findIndex
method. - Store the index in variable.
- Do a simple update like this:
yourArray[indexThatyouFind]
- 使用
findIndex
方法查找对象的索引。 - 将索引存储在变量中。
- 做一个这样的简单更新:
yourArray[indexThatyouFind]
//Initailize array of objects.
let myArray = [
{id: 0, name: "Jhon"},
{id: 1, name: "Sara"},
{id: 2, name: "Domnic"},
{id: 3, name: "Bravo"}
],
//Find index of specific object using findIndex method.
objIndex = myArray.findIndex((obj => obj.id == 1));
//Log object to Console.
console.log("Before update: ", myArray[objIndex])
//Update object's name property.
myArray[objIndex].name = "Laila"
//Log object to console again.
console.log("After update: ", myArray[objIndex])
回答by Bimal Grg
ES6way, without mutatingoriginal data.
ES6方式,不改变原始数据。
var projects = [
{
value: "jquery",
label: "jQuery",
desc: "the write less, do more, JavaScript library",
icon: "jquery_32x32.png"
},
{
value: "jquery-ui",
label: "jQuery UI",
desc: "the official user interface library for jQuery",
icon: "jqueryui_32x32.png"
}];
//find the index of object from array that you want to update
const objIndex = projects.findIndex(obj => obj.value === 'jquery-ui');
// make new object of updated object.
const updatedObj = { ...projects[objIndex], desc: 'updated desc value'};
// make final new array of objects by combining updated object.
const updatedProjects = [
...projects.slice(0, objIndex),
updatedObj,
...projects.slice(objIndex + 1),
];
console.log("original data=", projects);
console.log("updated data=", updatedProjects);
回答by kintaro
The best solution, thanks to ES6.
最好的解决方案,感谢 ES6。
This returns a new array with a replaced description for the object that contains a value equal to "jquery-ui".
这将返回一个新数组,其中包含一个等于“jquery-ui”的值的对象的替换描述。
const newProjects = projects.map(p =>
p.value === 'jquery-ui'
? { ...p, desc: 'new description' }
: p
);
回答by Frédéric Hamidi
回答by Ankit Kumar Rajpoot
Using map is the best solution without using extra libraries.(using ES6)
使用 map 是不使用额外库的最佳解决方案。(使用 ES6)
const state = [
{
userId: 1,
id: 100,
title: "delectus aut autem",
completed: false
},
{
userId: 1,
id: 101,
title: "quis ut nam facilis et officia qui",
completed: false
},
{
userId: 1,
id: 102,
title: "fugiat veniam minus",
completed: false
},
{
userId: 1,
id: 103,
title: "et porro tempora",
completed: true
}]
const newState = state.map(obj =>
obj.id === "101" ? { ...obj, completed: true } : obj
);
回答by user2765479
It's easily can be accomplished with underscore/lodash library:
可以使用下划线/lodash 库轻松完成:
_.chain(projects)
.find({value:"jquery-ui"})
.merge({desc: "new desc"});
Docs:
https://lodash.com/docs#find
https://lodash.com/docs#merge
文档:
https: //lodash.com/docs#find
https://lodash.com/docs#merge
回答by abe kur
you can use .find so in your example
你可以在你的例子中使用 .find so
var projects = [
{
value: "jquery",
label: "jQuery",
desc: "the write less, do more, JavaScript library",
icon: "jquery_32x32.png"
},
{
value: "jquery-ui",
label: "jQuery UI",
desc: "the official user interface library for jQuery",
icon: "jqueryui_32x32.png"
},
{
value: "sizzlejs",
label: "Sizzle JS",
desc: "a pure-JavaScript CSS selector engine",
icon: "sizzlejs_32x32.png"
}
];
let project = projects.find((p) => {
return p.value === 'jquery-ui';
});
project.desc = 'your value'
回答by elasticrash
you need to know the index of the object you are changing. then its pretty simple
您需要知道要更改的对象的索引。那么它很简单
projects[1].desc= "new string";
回答by tsadkan yitbarek
I think this way is better
我认为这种方式更好
const index = projects.findIndex(project => project.value==='jquery-ui');
projects[index].desc = "updated desc";