windows 拆分路径并在批处理脚本中取最后一个文件夹名称
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split path and take last folder name in batch script
提问by user2013
I want to split the string (having a path) with \and take last folder name in a variable. Please help.
我想拆分字符串（具有路径）\并在变量中取最后一个文件夹名称。请帮忙。
e.g
mypath=D:\FOLDER1\FOLDER2\FOLDER3\
例如
mypath=D:\FOLDER1\FOLDER2\FOLDER3\
I want FOLDER3 in a variable.
我想要一个变量中的 FOLDER3。
I tried with the command below which is working if the the last character is not \:
如果最后一个字符不是，我尝试使用下面的命令\：
for %f in (C:\FOLDER1\FOLDER2\FOLDER3) do set myfolder=%~nxf
It is not working if the last character is \
如果最后一个字符是 \
Also it is not working if variable is used like : for %f in (%mypath%) do set myfolder=%~nxf
如果像这样使用变量，它也不起作用： for %f in (%mypath%) do set myfolder=%~nxf
回答by user93353
@echo off
set MYDIR=C:\FOLDER1\FOLDER2\FOLDER3\
set MYDIR1=%MYDIR:~0,-1%
for %%f in (%MYDIR1%) do set myfolder=%%~nxf
echo %myfolder%
outputs
产出
FOLDER3
回答by Endoro
try:
尝试：
for %f in (C:\FOLDER1\FOLDER2\FOLDER3\.) do set myfolder=%~nxf
works also:
也有效：
for %f in (C:\FOLDER1\FOLDER2\FOLDER3.) do set myfolder=%~nxf
回答by Dirk
When your current folder contains spaces then try this:
当您的当前文件夹包含空格时，请尝试以下操作：
@echo off
for %%f in ("%CD%") do set LastPartOfFolder=%%~nxf
echo %LastPartOfFolder%
