java 线程“main”中的异常 javax.xml.ws.WebServiceException: 无法访问 WSDL ....(jax-ws)
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Exception in thread "main" javax.xml.ws.WebServiceException: Failed to access the WSDL....(jax-ws)
提问by user2010754
I have created a simple jax-ws web service and deployed it successfully. Then I created one client(jax-ws), but while running I am receiving the error below:
我创建了一个简单的 jax-ws Web 服务并成功部署了它。然后我创建了一个客户端（jax-ws），但是在运行时我收到以下错误：
Exception in thread "main" javax.xml.ws.WebServiceException: Failed to access the WSDL
at: file:./WEB-INF/wsdl/HelloService.wsdl. It failed with:.\WEB-INF\wsdl\HelloService.wsdl
But if I create the client (apache) for the same wsdl it is working. Please help.
但是如果我为同一个 wsdl 创建客户端（apache），它就可以工作。请帮忙。
This is the client file.import java.rmi.RemoteException;
这是客户端文件。导入 java.rmi.RemoteException;
public class MainClass {
public static void main(String[] args) throws RemoteException {
HelloPortProxy obj = new HelloPortProxy();
System.out.println(obj.sayhello("Everyone"));
System.out.println("Count:"+obj.getCheckVal());
}
}
回答by Paulius Matulionis
So whats not clear to you? The exception: javax.xml.ws.WebServiceException: Failed to access the WSDLclearly says to you that your web service's WSDLis not accessible within this path: /WEB-INF/wsdl/HelloService.wsdl.
所以你不清楚什么？例外情况：javax.xml.ws.WebServiceException: Failed to access the WSDL清楚地告诉您，您的 Web 服务WSDL无法在此路径中访问：/WEB-INF/wsdl/HelloService.wsdl.
If you've deployed your web service and you are able to access it through URL. For e.g.: http://somehost/somepath/YourService?wsdlthan create a JAX-WSclient like this:
如果您已经部署了 Web 服务并且可以通过URL. 例如：http://somehost/somepath/YourService?wsdl比创建这样的JAX-WS客户端：
try {
final String username = "someusername";
final String password = "somepassword";
Authenticator.setDefault(new Authenticator() {
@Override
protected PasswordAuthentication getPasswordAuthentication() {
return new PasswordAuthentication(
username,
password.toCharArray());
}
});
URL url = new URL("");
QName qname = new QName("http://somehost/somepath/YourService?wsdl", "YourService");
Service service = Service.create(url, qname);
YourService proxy = service.getPort(YourService.class);
Map<String, Object> requestContext = ((BindingProvider) proxy).getRequestContext();
requestContext.put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY, url.toString());
requestContext.put(BindingProvider.USERNAME_PROPERTY, username);
requestContext.put(BindingProvider.PASSWORD_PROPERTY, password);
} catch (Exception e) {
//Handle Error.
}
I've put the code with the basic authentication as well that you might need it in future. At the moment you can just remove it.
我已经将代码与基本身份验证以及您将来可能需要它一起放置。目前，您可以将其删除。
