php 设置标题( content-type: image/<ANY IMG FORMAT>)
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Set the header( content-type: image/<ANY IMG FORMAT>)
提问by user3663049
The php file that handles the images I display only allows one image format, either .jpg, .png, .bmp, etc but not all. The imageName stores the file name of the image stored in the database including its format. this is my code, so far it doesn't work yet and I'm not sure if that's allowed. Can you help me fix it please?
处理我显示的图像的 php 文件只允许一种图像格式，.jpg、.png、.bmp 等，但不是全部。imageName 存储数据库中存储的图像的文件名，包括其格式。这是我的代码，到目前为止它还不起作用，我不确定这是否允许。你能帮我修一下吗？
$con = mysqli_connect("localhost","root","","tickets");
$ticket = 109;
$result = mysqli_query($con,"SELECT image, imageName FROM tix WHERE tktNum=$ticket");
while($row = mysqli_fetch_array($result))
{
$image = $row['image'];
$imageName = $row['imageName'];
$format = substr( $imageName, -3 ); //gets the last 3 chars of the file name, ex: "photo1.png" gets the ".png" part
header('content-type: image/' . $format);
}
回答by John
I just used this, just indicating it's an image but without specifying image type.
我只是用了这个，只是表明它是一个图像，但没有指定图像类型。
header("Content-type: image");
It seems to be working just fine regardless of file type. I tested with IE, Firefox, Safari and the Android browser.
无论文件类型如何，它似乎都可以正常工作。我用 IE、Firefox、Safari 和 Android 浏览器进行了测试。
回答by D555
The solution is to read in the file and decide which kind of image it is and basednd on it send out the appropriate header.
解决方案是读入文件并决定它是哪种图像并基于它发送适当的标题。
$filename = basename($file);
$file_extension = strtolower(substr(strrchr($filename,"."),1));
switch( $file_extension ) {
case "gif": $ctype="image/gif"; break;
case "png": $ctype="image/png"; break;
case "jpeg":
case "jpg": $ctype="image/jpeg"; break;
case "svg": $ctype="image/svg+xml"; break;
default:
}
header('Content-type: ' . $ctype);
