Python 隐藏刻度但显示刻度标签

Python hide ticks but show tick labels

提问by user308827

I can remove the ticks with

我可以用

ax.set_xticks([]) 
ax.set_yticks([]) 

but this removes the labels as well. Any way I can plot the tick labels but not the ticks and the spine

但这也会删除标签。任何方式我都可以绘制刻度标签但不能绘制刻度和脊椎

采纳答案by Julien Spronck

You can set the tick length to 0 using tick_params(http://matplotlib.org/api/axes_api.html#matplotlib.axes.Axes.tick_params):

您可以使用tick_params（http://matplotlib.org/api/axes_api.html#matplotlib.axes.Axes.tick_params）将刻度长度设置为 0 ：

fig = plt.figure()
ax = fig.add_subplot(111)
ax.plot([1],[1])
ax.tick_params(axis=u'both', which=u'both',length=0)
plt.show()

回答by cmidi

matplotlib.pyplot.setp(*args, **kwargs)is used to set properties of an artist object. You can use this in addition to get_xticklabes()to make it invisible.

matplotlib.pyplot.setp(*args, **kwargs)用于设置艺术家对象的属性。除了get_xticklabes()使其不可见之外，您还可以使用它。

something on the lines of the following

以下内容

import matplotlib.pyplot as plt
fig = plt.figure()
ax = fig.add_subplot(2,1,1)
ax.set_xlabel("X-Label",fontsize=10,color='red')
plt.setp(ax.get_xticklabels(),visible=False)

Below is the reference page http://matplotlib.org/api/pyplot_api.html

以下是参考页面 http://matplotlib.org/api/pyplot_api.html

回答by mab

Thanks for your answers @julien-spronck and @cmidi.
As a note, I had to use both methods to make it work:

感谢您的回答@julien-spronck 和@cmidi。
请注意，我必须同时使用这两种方法才能使其工作：

import numpy as np
import matplotlib.pyplot as plt

fig, (ax1, ax2, ax3) = plt.subplots(1, 3, figsize=(11, 3))

data = np.random.random((4, 4))

ax1.imshow(data)
ax1.set(title='Bad', ylabel='$A_y$')
# plt.setp(ax1.get_xticklabels(), visible=False)
# plt.setp(ax1.get_yticklabels(), visible=False)
ax1.tick_params(axis='both', which='both', length=0)

ax2.imshow(data)
ax2.set(title='Somewhat OK', ylabel='$B_y$')
plt.setp(ax2.get_xticklabels(), visible=False)
plt.setp(ax2.get_yticklabels(), visible=False)
# ax2.tick_params(axis='both', which='both', length=0)

ax3.imshow(data)
ax3.set(title='Nice', ylabel='$C_y$')
plt.setp(ax3.get_xticklabels(), visible=False)
plt.setp(ax3.get_yticklabels(), visible=False)
ax3.tick_params(axis='both', which='both', length=0)

plt.show()

回答by Marcelo Villa-Pi?eros

You can set the yaxisand xaxisset_ticks_positionproperties so they just show on the left and bottom sides, respectively.

您可以设置yaxis和xaxisset_ticks_position属性，使它们分别显示在左侧和底部。

ax.yaxis.set_ticks_position('left')
ax.xaxis.set_ticks_position('bottom')

Furthermore, you can hide the spines as well by setting the set_visibleproperty of the specific spine to False.

此外，您还可以通过将set_visible特定脊椎的属性设置为 来隐藏脊椎False。

axes[i].spines['right'].set_visible(False)
axes[i].spines['top'].set_visible(False)

回答by Marcus

While attending a coursera course on Python, this was a question.

在参加有关 Python 的课程时，这是一个问题。

Below is the given solution, which I think is more readable and intuitive.

下面是给定的解决方案，我认为它更具可读性和直观性。

ax.tick_params(top='off', bottom='off', left='off', right='off', labelleft='on', labelbottom='on')

回答by Amir

Assuming that you want to remove some ticks on the Yaxes and only show the yticksthat correspond to the ticks that have values higher than 0 you can do the following:

假设您想删除Y轴上的一些刻度并仅显示yticks对应于值高于 0 的刻度的 ，您可以执行以下操作：

from import matplotlib.pyplot as plt

fig, ax = plt.subplots()

# yticks and yticks labels
yTicks = list(range(26))
yTicks = [yTick if yTick % 5 == 0 else 0 for yTick in yTicks]
yTickLabels = [str(yTick) if yTick % 5 == 0 else '' for yTick in yTicks]

Then you set up your axis object's Yaxes as follow:

然后Y按如下方式设置轴对象的轴：

ax.yaxis.grid(True)
ax.set_yticks(yTicks)
ax.set_yticklabels(yTickLabels, fontsize=6)
fig.savefig('temp.png')
plt.close()

And you'll get a plot like this:

你会得到一个这样的情节：

回答by Valerie

This worked for me:

这对我有用：

plt.tick_params(axis='both', labelsize=0, length = 0)