java 迄今为止的字符串解析：非法模式字符“T”。
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Parsing string to date: Illegal pattern character 'T'.
提问by mbezunartea
I need to parse a string to date in java. My string has the following format:
我需要在java中解析一个字符串到日期。我的字符串具有以下格式：
2014-09-17T12:00:44.0000000Z
but java throws the following exception when trying to parse such format... java.lang.IllegalArgumentException: Illegal pattern character 'T'.
但Java试图解析这种格式时抛出以下异常... java.lang.IllegalArgumentException: Illegal pattern character 'T'。
Any ideas on how to parse that?
关于如何解析它的任何想法？
Thank you!
谢谢！
回答by Meno Hochschild
Given your input of 2014-09-17T12:00:44.0000000Z, it is not sufficient to escape the letter Tonly. You also have to handle the trailing Z. But be aware, this Zis NOT a literal, but has the meaning of UTC+00:00timezone offset according to ISO-8601-standard. So escaping Zis NOT correct.
鉴于您输入的2014-09-17T12:00:44.0000000Z，T仅对字母进行转义是不够的。您还必须处理尾随Z. 但请注意，这Z不是文字，而是UTC+00:00根据ISO-8601-standard. 所以逃避Z是不正确的。
SimpleDateFormathandles this special char Zby pattern symbol X. So the final solution looks like:
SimpleDateFormatZ通过模式符号处理这个特殊字符X。所以最终的解决方案看起来像：
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSSSSSX");
Date d = sdf.parse("2014-09-17T12:00:44.0000000Z");
System.out.println(d); // output: Wed Sep 17 14:00:44 CEST 2014
Note that the different clock time is right for timezone CEST(toString()uses system timezone), and that the result is equivalent to UTC-time 12:00:44. Furthermore, I had to insert seven symbols S in order to correctly process your input which pretends to have precision down to 100ns(although Java pre 8 can only process milliseconds).
请注意，不同的时钟时间适用于时区CEST（toString()使用系统时区），并且结果等效于UTC-time 12:00:44. 此外，我必须插入七个符号 S 才能正确处理假装精度低至的输入100ns（尽管 Java pre 8 只能处理毫秒）。
回答by Xavier Delamotte
You have to escape the 'T' character:
您必须转义“T”字符：
SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'", Locale.US);
format.setTimeZone(TimeZone.getTimeZone("UTC"));
Date parse = format.parse("2014-09-17T12:00:44.0000000Z");
Using Answer to: What is this date format? 2011-08-12T20:17:46.384Z
使用 Answer to:这是什么日期格式？2011-08-12T20:17:46.384Z
回答by venkatesh.khandare
Try this.
试试这个。
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.Date;
public class DateClass {
public static void main(String[] args) throws ParseException {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
Date d = sdf.parse("2014-09-17T12:00:44.0000000Z");
System.out.println(d); //output Wed Sep 17 12:00:44 IST 2014
}
}
