Python：函数在没有 max() 的情况下返回列表中的最高值？
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Python: Function returning highest value in list without max()?
提问by rlo5029
I need to write a function that takes a list of numbers as the parameter and returns the largest number in the list without using max().
我需要编写一个函数，它将数字列表作为参数并返回列表中的最大数字而不使用max().
I've tried:
我试过了：
def highestNumber(l):
myMax = 0
if myMax < l:
return myMax
return l
print highestNumber ([77,48,19,17,93,90])
...and a few other things that I can't remember. I just need to understand how to loop over elements in a list.
……还有一些我不记得的事情。我只需要了解如何循环列表中的元素。
采纳答案by thefourtheye
def highestNumber(l):
myMax = l[0]
for num in l:
if myMax < num:
myMax = num
return myMax
print highestNumber ([77,48,19,17,93,90])
Output
输出
93
Or You can do something like this
或者你可以做这样的事情
def highestNumber(l):
return sorted(l)[-1]
Or
或者
def highestNumber(l):
l.sort()
return l[-1]
回答by Martijn Pieters
You need to loop over all values to determine the maximum; keep track of the maximum so farand return that after completing the loop:
您需要遍历所有值以确定最大值；跟踪到目前为止的最大值并在完成循环后返回：
def highestNumber(l):
myMax = float('-inf')
for i in l:
if i > myMax:
myMax = i
return myMax
Here, float('-inf')is a number guaranteed to be lower than any other number, making it a great starting point.
在这里，float('-inf')是一个保证低于任何其他数字的数字，使其成为一个很好的起点。
The forconstruct takes care of all the looping; you do that directly over the elements of l, iis assigned each element of the sequence, one by one.
该for构造负责所有循环；你这样做正上方的元件l，i被分配序列的每个元素，一个接一个。
Your code forgets to loop, tests the whole list against 0and returns the whole list if the test failed.
您的代码忘记循环，测试整个列表0并在测试失败时返回整个列表。
回答by RAMPRASAD REDDY GOPU
function to find maximum in a list without using predefined functions
在不使用预定义函数的情况下在列表中查找最大值的函数
def max_len_list(temp):
i=1
for each in temp:
while i < max_len:
comp=each;
if comp > temp[i]:
i=i+1;
elif temp[i] > comp:
comp=temp[i];
i=i+1
return comp
list1 = [];
max_len=3;
try:
while len(list1) < max_len :
no = int(input("enter a number\n"));
list1.append(no);
except:
print "enter number not string"
max_no=max_len_list(list1);
print max_no
