javascript 验证逗号分隔的电子邮件列表
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Validate a comma separated email list
提问by user2256799
I'm trying to come up with a regular expression to validate a comma separated email list.
我正在尝试提出一个正则表达式来验证逗号分隔的电子邮件列表。
I would like to validate the complete list in the first place, then split(";"), then trim each array value (each email) from the split.
我想首先验证完整列表，然后拆分（“;”），然后从拆分中修剪每个数组值（每个电子邮件）。
I would like to validate the following expressions:
我想验证以下表达式：
EMAIL,EMAIL --> Ok
EMAIL, EMAIL --> Ok
EMAIL , EMAIL --> Ok
EMAIL , , EMAIL --> Wrong
EMAIL , notAnEmail , EMAIL --> Wrong
I know there's many complex expressions for validating emails but I don't need anything fancy, this just works for me: /\S+@\S+\.\S+/;
我知道验证电子邮件有很多复杂的表达式，但我不需要任何花哨的东西，这对我有用： /\S+@\S+\.\S+/;
I would like plain and simple JS, not jQuery. Thanks.
我想要简单明了的 JS，而不是 jQuery。谢谢。
Edit: I've already considered fist validate then split, but with the expressions I've tried so far, this will be validated as two correct emails:
编辑：我已经考虑过先验证然后拆分，但是使用到目前为止我尝试过的表达式，这将被验证为两个正确的电子邮件：
EMAIL, EMAIL . EMAIL
I would like to validate the list itself as much as every email.
我想和每封电子邮件一样验证列表本身。
回答by Anonymoose
An easier way would be to remove spaces and split the string first:
更简单的方法是删除空格并首先拆分字符串：
var emails = emailList.replace(/\s/g,'').split(",");
This will create an array. You can then iterate over the array and check if the element is not empty and a valid emailadres.
这将创建一个数组。然后，您可以遍历数组并检查元素是否为空且是否为有效的 emailadres。
var valid = true;
var regex = /^(([^<>()[\]\.,;:\s@\"]+(\.[^<>()[\]\.,;:\s@\"]+)*)|(\".+\"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/;
for (var i = 0; i < emails.length; i++) {
if( emails[i] == "" || ! regex.test(emails[i])){
valid = false;
}
}
note: I got the the regex from here
注意：我从这里得到了正则表达式
回答by Felipe Alarcon
Also note that you'll want to get rid of extra spaces so an extra step needs to be added as follows:
另请注意，您需要删除额外的空格，因此需要添加一个额外的步骤，如下所示：
var emailStr = "[email protected] , [email protected], [email protected]\n";
function validateEmailList(raw){
var emails = raw.split(',')
var valid = true;
var regex = /^(([^<>()[\]\.,;:\s@\"]+(\.[^<>()[\]\.,;:\s@\"]+)*)|(\".+\"))@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\])|(([a-zA-Z\-0-9]+\.)+[a-zA-Z]{2,}))$/;
for (var i = 0; i < emails.length; i++) {
if( emails[i] === "" || !regex.test(emails[i].replace(/\s/g, ""))){
valid = false;
}
}
return valid;
}
console.log(validateEmailList(emailStr))
By adding .replace(/\s/g, "")you make sure all spaces including new lines and tabs are removed. the outcome of the sample is true as we are getting rid of all spaces.
通过添加，.replace(/\s/g, "")您可以确保删除所有空格，包括新行和制表符。样本的结果是真实的，因为我们正在摆脱所有空间。
回答by sshashank124
I agree with @crisbeto's comment but if you are sure that this is how you want to do it, you can do it by matching the following regex:
我同意@crisbeto 的评论，但如果您确定这是您想要的方式，您可以通过匹配以下正则表达式来完成：
^(\s?[^\s,]+@[^\s,]+\.[^\s,]+\s?,)*(\s?[^\s,]+@[^\s,]+\.[^\s,]+)$
^(\s?[^\s,]+@[^\s,]+\.[^\s,]+\s?,)*(\s?[^\s,]+@[^\s,]+\.[^\s,]+)$
回答by Sunny_Sid
I am using the Regex from many years and code is same. I believe this works for every one:
我使用了多年的正则表达式，代码相同。我相信这对每个人都有效：
^(\w+((-\w+)|(\.\w+))*\@[A-Za-z0-9]+((\.|-)[A-Za-z0-9]+)*\.[A-Za-z0-9]{2,4}\s*?,?\s*?)+$
Be happy :)
要开心 ：）
